The mean is 8.
In order to find the weighted mean of this set of the data, we need to know the weight for each data in the set, and this information is not given in your question.Definition: When each number ai is to have weight wi, the weighted mean is equal to(w1a1+w2a2 + ... + wnan)/(w1 + w2 + ... + wn).
The mean, or average, of a data set is equal to the sum of all the data points divided by the number of data points there are. In this case, you have 11 points of data. So, this is what you'll want to do:(3+12+28+12+12+13+15+26+16+12+27)/(11) = 176/11 = 16The mean is 16.
Whatever you like. The median value for each of the following three sets is 10. For the set {1, 9, 11, 12}. the mean is 8.25, smaller than the median. For the set {1, 9, 15, 15}. the mean is 10, the same as the median. For the set {1, 9, 15, 16}. the mean is 10.25, larger than the median.
16,11,18,11,15,17,11
The mean is 8 because: (1+6+10+11+12)/5=8 We know that the Arithmetic Mean of a data set = (sum of all the items)/ number of items. =(1+6+10+11+12)/5 =(40)/5 =8. The Arithmetic Mean of 1, 6, 10, 11, and 12 is 8.
The mode is the data set element(s) that is(are) repeated the most. If every data set element occurs the same number of times, there is no mode. As there is only one occurrence of each data set element in {11, 12, 13} there is no mode. If your data set read {11, 12, 12, 13, 13, 12} your mode would be 12. If your data set read {11, 12, 12, 13, 13} your modes would be 12 & 13.
In order to find the weighted mean of this set of the data, we need to know the weight for each data in the set, and this information is not given in your question.Definition: When each number ai is to have weight wi, the weighted mean is equal to(w1a1+w2a2 + ... + wnan)/(w1 + w2 + ... + wn).
The mean, or average, of a data set is equal to the sum of all the data points divided by the number of data points there are. In this case, you have 11 points of data. So, this is what you'll want to do:(3+12+28+12+12+13+15+26+16+12+27)/(11) = 176/11 = 16The mean is 16.
Whatever you like. The median value for each of the following three sets is 10. For the set {1, 9, 11, 12}. the mean is 8.25, smaller than the median. For the set {1, 9, 15, 15}. the mean is 10, the same as the median. For the set {1, 9, 15, 16}. the mean is 10.25, larger than the median.
11
16,11,18,11,15,17,11
The variance of this data set is 22.611
The mean is 8 because: (1+6+10+11+12)/5=8 We know that the Arithmetic Mean of a data set = (sum of all the items)/ number of items. =(1+6+10+11+12)/5 =(40)/5 =8. The Arithmetic Mean of 1, 6, 10, 11, and 12 is 8.
2
11
Let the data set be 3,4,5,6,7,8. First put the data in rank order ; already done!!!! To find the MEDIAN , we tak the two middle numbers, '5' & '6' in this case. Then (5 + 6) / 2 = 11/2 = 5.5 5.5 is the Median.
Let write the data in an increasing order: p q r s t.Since the median is 14, then r = 14, and we have: p q 14 s t.Since the mode is 11, then p = q = 11.Since the range is 9, then t - p = 9, t - 11 = 9, and t = 20.So, we have: 11 11 14 s 20.Since the mean is 25, we have:(11 + 11 + 14 + s + 20)/5 = 25(56 + s)/5 = 25 multiply by 5 to both sides56 + s = 125 subtract 56 to both sidess = 69So the data set is: 11 11 14 69 20