To determine the measure of angle ACD, more information is needed, such as the context of the geometric figure, any given angles, or relevant side lengths. Without specific details or a diagram, it's impossible to provide an accurate measure for angle ACD. Please provide additional information for clarification.
Label the triangle ABC. Draw the bisector of angle A to meet BC at D. Then in triangles ABD and ACD, angle ABD = angle ACD (equiangular triangle) angle BAD = angle CAD (AD is angle bisector) so angle ADB = angle ACD (third angle of triangles). Also AD is common. So, by ASA, triangle ABD is congruent to triangle ACD and therefore AB = AC. By drawing the bisector of angle B, it can be shown that AB = BC. Therefore, AB = BC = AC ie the triangle is equilateral.
To prove that triangle ABC is congruent to triangle DBC given that line CB bisects angle ACD, we can use the Angle-Side-Angle (ASA) postulate. Proof: | Statements | Reasons | |---------------------------------------------------|------------------------------------------| | 1. CB bisects angle ACD. | 1. Given. | | 2. Angle ACB ≅ Angle DCB. | 2. Definition of angle bisector. | | 3. Line CB is common to both triangles ABC and DBC. | 3. Common side. | | 4. Triangle ABC ≅ Triangle DBC. | 4. ASA Postulate (Angle ACB ≅ Angle DCB, CB is common, and Angle ACD is shared). |
they both measure the angle in degrees
each measure of the angle at point h has a measure of
the answer is twice. the angle of rotation is twice the measure
TRUE
Label the triangle ABC. Draw the bisector of angle A to meet BC at D. Then in triangles ABD and ACD, angle ABD = angle ACD (equiangular triangle) angle BAD = angle CAD (AD is angle bisector) so angle ADB = angle ACD (third angle of triangles). Also AD is common. So, by ASA, triangle ABD is congruent to triangle ACD and therefore AB = AC. By drawing the bisector of angle B, it can be shown that AB = BC. Therefore, AB = BC = AC ie the triangle is equilateral.
That is not necessarily true.
To prove that triangle ABC is congruent to triangle DBC given that line CB bisects angle ACD, we can use the Angle-Side-Angle (ASA) postulate. Proof: | Statements | Reasons | |---------------------------------------------------|------------------------------------------| | 1. CB bisects angle ACD. | 1. Given. | | 2. Angle ACB ≅ Angle DCB. | 2. Definition of angle bisector. | | 3. Line CB is common to both triangles ABC and DBC. | 3. Common side. | | 4. Triangle ABC ≅ Triangle DBC. | 4. ASA Postulate (Angle ACB ≅ Angle DCB, CB is common, and Angle ACD is shared). |
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That is not necessarily true.
Suppose you have triangle ABC with base BC, and angle B = angle C. Draw the altitude AD.Considers triangles ABD and ACDangle ABD = angle ACD (given)angle ADB = 90 deg = angle ACDtherefore angle BAD = angle CADAlso the side AD is common to the two triangles.Therefore triangle ABD is congruent to triangle ACD (ASA) and so AB = AC.That is, triangle ABC is isosceles.
the measure of an angle is the degrees of an angle.
you can measure a angle with a protracte.
they both measure the angle in degrees
The measure of the obtuse angle would then be double that of the acute angle.
The measure of the exterior angle.