To determine the measure of angle ACD, more information is needed, such as the context of the geometric figure, any given angles, or relevant side lengths. Without specific details or a diagram, it's impossible to provide an accurate measure for angle ACD. Please provide additional information for clarification.
Label the triangle ABC. Draw the bisector of angle A to meet BC at D. Then in triangles ABD and ACD, angle ABD = angle ACD (equiangular triangle) angle BAD = angle CAD (AD is angle bisector) so angle ADB = angle ACD (third angle of triangles). Also AD is common. So, by ASA, triangle ABD is congruent to triangle ACD and therefore AB = AC. By drawing the bisector of angle B, it can be shown that AB = BC. Therefore, AB = BC = AC ie the triangle is equilateral.
To prove that triangle ABC is congruent to triangle DBC given that line CB bisects angle ACD, we can use the Angle-Side-Angle (ASA) postulate. Proof: | Statements | Reasons | |---------------------------------------------------|------------------------------------------| | 1. CB bisects angle ACD. | 1. Given. | | 2. Angle ACB ≅ Angle DCB. | 2. Definition of angle bisector. | | 3. Line CB is common to both triangles ABC and DBC. | 3. Common side. | | 4. Triangle ABC ≅ Triangle DBC. | 4. ASA Postulate (Angle ACB ≅ Angle DCB, CB is common, and Angle ACD is shared). |
they both measure the angle in degrees
each measure of the angle at point h has a measure of
the answer is twice. the angle of rotation is twice the measure
TRUE
Label the triangle ABC. Draw the bisector of angle A to meet BC at D. Then in triangles ABD and ACD, angle ABD = angle ACD (equiangular triangle) angle BAD = angle CAD (AD is angle bisector) so angle ADB = angle ACD (third angle of triangles). Also AD is common. So, by ASA, triangle ABD is congruent to triangle ACD and therefore AB = AC. By drawing the bisector of angle B, it can be shown that AB = BC. Therefore, AB = BC = AC ie the triangle is equilateral.
That is not necessarily true.
m<ACD ron duce was here
That is not necessarily true.
Suppose you have triangle ABC with base BC, and angle B = angle C. Draw the altitude AD.Considers triangles ABD and ACDangle ABD = angle ACD (given)angle ADB = 90 deg = angle ACDtherefore angle BAD = angle CADAlso the side AD is common to the two triangles.Therefore triangle ABD is congruent to triangle ACD (ASA) and so AB = AC.That is, triangle ABC is isosceles.
the measure of an angle is the degrees of an angle.
you can measure a angle with a protracte.
they both measure the angle in degrees
The measure of the obtuse angle would then be double that of the acute angle.
The measure of the exterior angle.
No cheating!