the midpoints for points (-8, 5) and (2, -2) is (-3, 1.5)
It is: (9+5)/2 and (8+2)/2 which is 7 and 5 Midpoint: (7, 5)
It is 1.5
To find the coordinate for the midpoint, divide the differences in the X and Y positions by 2 and add to the lesser or subtract from the greater coordinate (the result has to be in between)X: from -9 to 5 is 14 units 14/2 =7-9 + 7 = -2Y: from 8 to -2 is 10 units 10/2 = 5-2 + 5 = 3The midpoint of AB is {-2;3}
Endpoints: (-8, 12) and (-13, -2) Midpoint: (-10.5, 5)
Midpoint: (-10.5, 5)
If you mean points of (-2, 5) and (4, 8) then the midpoint is at (1, 6.5)
midpoint: (8, 5)
It is: (9+5)/2 and (8+2)/2 which is 7 and 5 Midpoint: (7, 5)
It is 1.5
To find the coordinate for the midpoint, divide the differences in the X and Y positions by 2 and add to the lesser or subtract from the greater coordinate (the result has to be in between)X: from -9 to 5 is 14 units 14/2 =7-9 + 7 = -2Y: from 8 to -2 is 10 units 10/2 = 5-2 + 5 = 3The midpoint of AB is {-2;3}
Endpoints: (-8, 12) and (-13, -2) Midpoint: (-10.5, 5)
If you mean: (2, 2) and (8, -6) Then midpoint: (2+8)/2 and (2-6)/2 which is (4, -2)
Midpoint: (-10.5, 5)
The midpoint is the point (-10.5, 5) .
Midpoint: (8, 7)
To find the midpoint of the line segment with endpoints (-8, 12) and (-13, -2), use the midpoint formula: ((x_m, y_m) = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)). Plugging in the values, we get (x_m = \frac{-8 + (-13)}{2} = \frac{-21}{2} = -10.5) and (y_m = \frac{12 + (-2)}{2} = \frac{10}{2} = 5). Therefore, the midpoint is ((-10.5, 5)).
center or midpoint is (-2, 5)