The given sequence is -2, -4, -6, which is an arithmetic sequence where each term decreases by 2. The first term (a) is -2, and the common difference (d) is -2. The nth term can be expressed using the formula ( a_n = a + (n-1)d ). Thus, the nth term is given by ( a_n = -2 + (n-1)(-2) = -2n ).
The sequence 4, 6, 8, 10 is an arithmetic sequence where each term increases by 2. The nth term formula can be expressed as ( a_n = 4 + (n - 1) \cdot 2 ). Simplifying this gives ( a_n = 2n + 2 ). Thus, the nth term of the sequence is ( 2n + 2 ).
The sequence 8, 6, 4, 2, 0 is an arithmetic sequence with a common difference of -2. The first term (a) is 8, and the common difference (d) is -2. The nth term can be expressed using the formula: ( T_n = a + (n-1)d ). Thus, the nth term is given by ( T_n = 8 + (n-1)(-2) = 10 - 2n ).
To find the nth term of the sequence 4, 13, 28, 49, 76, we first identify the differences between consecutive terms: 9, 15, 21, 27. The second differences, which are constant at 6 (6, 6, 6), suggest that the sequence is quadratic. The nth term can be expressed as ( an^2 + bn + c ). By solving the equations based on the first few terms, we find the nth term is ( n^2 + 3n ).
To find the nth term of the sequence 4, 10, 18, 28, 40, we first identify the pattern in the differences between consecutive terms: 6, 8, 10, and 12. The second differences are constant at 2, indicating a quadratic sequence. The nth term can be expressed as ( a_n = n^2 + n + 2 ). Thus, the nth term of the sequence is ( n^2 + n + 2 ).
If you mean nth term 2n then the 1st four terms are 2 4 6 and 8
The nth term is (2n - 12).
If you mean: 3, 4, 5, 6 and 7 then nth term = n+2
The sequence 4, 6, 8, 10 is an arithmetic sequence where each term increases by 2. The nth term formula can be expressed as ( a_n = 4 + (n - 1) \cdot 2 ). Simplifying this gives ( a_n = 2n + 2 ). Thus, the nth term of the sequence is ( 2n + 2 ).
It is: nth term = -4n+14
If the nth term is 8 -2n then the 1st four terms are 6, 4, 2, 0 and -32 is the 20th term number
The sequence 8, 6, 4, 2, 0 is an arithmetic sequence with a common difference of -2. The first term (a) is 8, and the common difference (d) is -2. The nth term can be expressed using the formula: ( T_n = a + (n-1)d ). Thus, the nth term is given by ( T_n = 8 + (n-1)(-2) = 10 - 2n ).
The nth term is 2n So the 20th term is 2 x 20 = 40.
1 2 3 4= n 2 4 6 8 plusing two = 2n answer 2n
Ah, what a lovely sequence you have there! To find the nth term, you notice that each number is increasing by 2. So, if we start at 6, the nth term can be represented by the formula 2n + 4. Happy calculating, my friend!
To find the nth term of the sequence 4, 13, 28, 49, 76, we first identify the differences between consecutive terms: 9, 15, 21, 27. The second differences, which are constant at 6 (6, 6, 6), suggest that the sequence is quadratic. The nth term can be expressed as ( an^2 + bn + c ). By solving the equations based on the first few terms, we find the nth term is ( n^2 + 3n ).
The nth term of the sequence is (n + 1)2 + 2.
The nth term is 9n-2