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What is the first four terms of the sequence term 2x position number?
If you mean nth term 2n then the 1st four terms are 2 4 6 and 8
Nth term of 6 8 10 12?
It is: 2n+4
What is the nth of -10-8-6-4?
2
What is the nth term for 18 12 6 0 -6?
The nth term of that series is (24 - 6n).
What is the nth term of -2 -6 -10 -14?
By varying the parameters of a quartic polynomial, the nth term can be made whatever you like. But, taking the simplest solution, Un = 2 - 4n for
What is the nth term of -10 -8 -6 -4 -2?
The nth term is (2n - 12).
What is the nth term for a sequence 34567?
If you mean: 3, 4, 5, 6 and 7 then nth term = n+2
What is the nth term for 10 6 2 -2?
It is: nth term = -4n+14
What are the first four terms of a sequence and what term number is -32 when the nth term is 8 -2n?
If the nth term is 8 -2n then the 1st four terms are 6, 4, 2, 0 and -32 is the 20th term number
What is the twentieth term of 2 4 6 8?
The nth term is 2n So the 20th term is 2 x 20 = 40.
What is the nth term for 4 5 6 7 8?
what is the nth term of 4,5,6,7,8
What is the nth term of the number 2 4 6 8?
1 2 3 4= n 2 4 6 8 plusing two = 2n answer 2n
What is the nth term for 6 11 18 27 38?
The nth term of the sequence is (n + 1)2 + 2.
What is the nth term of 7 16 25 34 43?
The nth term is 9n-2
What is the nth term of the sequence 4 6 8 10?
Un = 2n + 2 is one possible answer.
What is the nth term of 3 6 11 18 27?
The given sequence is an arithmetic sequence with a common difference that increases by 1 with each term. To find the nth term of an arithmetic sequence, you can use the formula: nth term = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. In this case, the first term (a) is 3 and the common difference (d) is increasing by 1, so the nth term would be 3 + (n-1)(n-1) = n^2 + 2.
What is the nth term 6 8 10 12?
The given sequence 6, 8, 10, 12 is an arithmetic sequence with a common difference of 2 between each term. To find the nth term of an arithmetic sequence, you can use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term (a_1) is 6 and the common difference (d) is 2. So, the nth term (a_n = 6 + (n-1)2 = 2n + 4).
