7n - 3
It is: 25-7n
Un = 25 - 7n
The nth term is 7n-3 and so the next term will be 39
tn = 34 - 9n where n = 1,2,3,...
To find the nth term of the sequence 3, 11, 25, 45, we first look for a pattern in the differences between the terms. The first differences are 8, 14, and 20, and the second differences are 6, 6, indicating that the sequence is quadratic. We can express the nth term as ( a_n = An^2 + Bn + C ). Solving for A, B, and C using the given terms, we find the nth term is ( a_n = 3n^2 - 3n + 3 ).
It is: 25-7n
Un = 25 - 7n
The nth term is 7n-3 and so the next term will be 39
The given sequence is an arithmetic sequence with a common difference of 7 (18-11=7, 25-18=7, and so on). To find the nth term of an arithmetic sequence, you can use the formula: a_n = a_1 + (n-1)d, where a_n is the nth term, a_1 is the first term, n is the position of the term, and d is the common difference. In this case, the first term a_1 is 11 and the common difference d is 7. So, the nth term of this sequence is 11 + (n-1)7, which simplifies to 11 + 7n - 7, or 7n + 4.
The next term is 45 because the numbers are increasing by increments of 3 5 7 9 and then 11
3n^2 - n + 1
tn = 34 - 9n where n = 1,2,3,...
To find the nth term of the sequence 3, 11, 25, 45, we first look for a pattern in the differences between the terms. The first differences are 8, 14, and 20, and the second differences are 6, 6, indicating that the sequence is quadratic. We can express the nth term as ( a_n = An^2 + Bn + C ). Solving for A, B, and C using the given terms, we find the nth term is ( a_n = 3n^2 - 3n + 3 ).
The nth term is: 5-6n
The nth term is 9n-2
To determine the nth term of the sequence 25, 16, 7, we first identify the pattern. The sequence appears to be decreasing by 9, then by 9 again, suggesting a consistent difference. This leads to a formula for the nth term: ( a_n = 34 - 9n ), where ( a_1 = 25 ) for n=1. Thus, the nth term can be expressed as ( a_n = 34 - 9n ).
The nth term is 6n+1 and so the next term will be 31