To find the nth term of this sequence, we first need to determine the pattern or rule governing the sequence. By examining the differences between consecutive terms, we can see that the sequence is increasing by 9, 15, 21, 27, and so on. This indicates that the nth term is given by the formula n^2 + 1.
It is: nth term = 35-9n
It is: 26-6n
The common difference (d) between successive terms is -9. The first term (a) is 26 The formula for the nth term [a(n)] of an Arithmetic Series is , a + (n - 1)d. Inputting the values for a and d gives :- a(n) = 26 - 9(n - 1) = 26 - 9n + 9 = 35 - 9n......where n = 1,2,3......
107 ÷ 26 = 4 with remainder 3
36
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
It is: nth term = 7n-9
It is: nth term = 35-9n
Tn = 10 + n2
46n9
It is: 26-8n
Here are the first five terms of a sequence. 12 19 26 33 40 Find an expression for the nth term of this sequence.
[ 6n + 8 ] is.
It is: 26-6n
The common difference (d) between successive terms is -9. The first term (a) is 26 The formula for the nth term [a(n)] of an Arithmetic Series is , a + (n - 1)d. Inputting the values for a and d gives :- a(n) = 26 - 9(n - 1) = 26 - 9n + 9 = 35 - 9n......where n = 1,2,3......
t(n) = 4n2 - 4n + 2
Expressed in terms of n, the nth term is equal to 7n - 2.