To find the pattern in the sequence 1, 4, 11, 22, 37, we can see that the differences between consecutive terms are 3, 7, 11, and 15, respectively. These are consecutive odd numbers, starting from 3. This means the nth term of the sequence can be expressed as n^2 + 2. So, the nth term of this sequence is n^2 + 2.
Oh, what a happy little sequence we have here! To find the pattern and the nth term, we can see that each number is increasing by adding consecutive odd numbers (3, 7, 11, 15...). The nth term of this sequence can be found using the formula: nth term = 1 + n^2 + (n-1), where n represents the position of the term in the sequence.
nth term = 5 +8n
46n9
The problem is finding the next term 7 9 13 21 37 69 133 261......... nth the first number aka the N1 = 7, N2 = 9, N3= 13,....... N7= 133,........Nth The first number 7 +2 = 9, which is the second number NOTE: 21=2 the second number 9 + 4 = 13 NOTE: 22=4 the third 13 + 8 = 21 NOTE: 23=8 the fourth 21 +16 = 37 NOTE: 24=16 So, the pattern is Nm+2m= the next number in the pattern Nth = Nth-1+2th-1 By: Rodney T. Anderson
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1
It seems each term(except the first one obviously) is generated by adding 11 to previous one. 4 15 = 4 + 11 26 = 15 + 11 37 = 26 + 11 The next term in the sequence will be then: 48 = 37 + 11
The nth term is 7n-3 and so the next term will be 39
nth term = 5 +8n
46n9
37 - 9n
The nth term is 7n-5 and so the 6th term will be 37
37
The problem is finding the next term 7 9 13 21 37 69 133 261......... nth the first number aka the N1 = 7, N2 = 9, N3= 13,....... N7= 133,........Nth The first number 7 +2 = 9, which is the second number NOTE: 21=2 the second number 9 + 4 = 13 NOTE: 22=4 the third 13 + 8 = 21 NOTE: 23=8 the fourth 21 +16 = 37 NOTE: 24=16 So, the pattern is Nm+2m= the next number in the pattern Nth = Nth-1+2th-1 By: Rodney T. Anderson
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1
It seems each term(except the first one obviously) is generated by adding 11 to previous one. 4 15 = 4 + 11 26 = 15 + 11 37 = 26 + 11 The next term in the sequence will be then: 48 = 37 + 11
go ask your teacher and tell him hes dumb
One method is an = n2 +1.So the first term is 1+1the second is 22 +1=5the third is 32 +1=10the fourth is 16+1=17 etc.There is also a recursive way to find it. I only point it out so you can see there may be more than one way to denote the nth term in a sequence. This method uses recursion.2+0=2=a12+3=5=a25+5=10 =a310+7=17 =a417+9=26 =a526+11=37 =a6So nth term is easy recursivelynth term=an =an-1 +(2(n-1)+1) =an-1 +(2n-1) =for example n=4 is the 4th term.a4 =a3 +(8-1)=10+7=17the 5th term a5 =17+(2x5-1)=17+9=26
It is increasing by 4 and the nth term is 4n+1