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1 +3 =4 +3+4 =11 +3+4+4 =22 +3+4+4+4 37 +3+4+4+4+4 .... u can c where i am goin here

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Q: What is the nth term of 1 4 11 22 and 37?

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nth term = 5 +8n

46n9

The problem is finding the next term 7 9 13 21 37 69 133 261......... nth the first number aka the N1 = 7, N2 = 9, N3= 13,....... N7= 133,........Nth The first number 7 +2 = 9, which is the second number NOTE: 21=2 the second number 9 + 4 = 13 NOTE: 22=4 the third 13 + 8 = 21 NOTE: 23=8 the fourth 21 +16 = 37 NOTE: 24=16 So, the pattern is Nm+2m= the next number in the pattern Nth = Nth-1+2th-1 By: Rodney T. Anderson

As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1

It seems each term(except the first one obviously) is generated by adding 11 to previous one. 4 15 = 4 + 11 26 = 15 + 11 37 = 26 + 11 The next term in the sequence will be then: 48 = 37 + 11

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The nth term is 7n-3 and so the next term will be 39

nth term = 5 +8n

46n9

37 - 9n

The nth term is 7n-5 and so the 6th term will be 37

37

The problem is finding the next term 7 9 13 21 37 69 133 261......... nth the first number aka the N1 = 7, N2 = 9, N3= 13,....... N7= 133,........Nth The first number 7 +2 = 9, which is the second number NOTE: 21=2 the second number 9 + 4 = 13 NOTE: 22=4 the third 13 + 8 = 21 NOTE: 23=8 the fourth 21 +16 = 37 NOTE: 24=16 So, the pattern is Nm+2m= the next number in the pattern Nth = Nth-1+2th-1 By: Rodney T. Anderson

As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1

It seems each term(except the first one obviously) is generated by adding 11 to previous one. 4 15 = 4 + 11 26 = 15 + 11 37 = 26 + 11 The next term in the sequence will be then: 48 = 37 + 11

go ask your teacher and tell him hes dumb

One method is an = n2 +1.So the first term is 1+1the second is 22 +1=5the third is 32 +1=10the fourth is 16+1=17 etc.There is also a recursive way to find it. I only point it out so you can see there may be more than one way to denote the nth term in a sequence. This method uses recursion.2+0=2=a12+3=5=a25+5=10 =a310+7=17 =a417+9=26 =a526+11=37 =a6So nth term is easy recursivelynth term=an =an-1 +(2(n-1)+1) =an-1 +(2n-1) =for example n=4 is the 4th term.a4 =a3 +(8-1)=10+7=17the 5th term a5 =17+(2x5-1)=17+9=26

It is increasing by 4 and the nth term is 4n+1