There are infinitely many polynomials of order 6 that will give these as the first six numbers and any one of these could be "the" rule. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
For example,
U(n) = 0.1*n^6 - 2.1*n^5 + 17.5*n^4 - 73.5n^3 + 164.4*n^2 - 206.4*n + 184 will do the trick.
The simplest solution, based on a polynomial of degree 2, is
V(n) = 2*n^2 - 30*n + 112.
If you mean: 6 12 18 24 then the nth term is 6n
To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 4, then 8, then 12, then 16, and so on. This pattern suggests that the nth term can be represented by the formula n^2 + n, where n is the position of the term in the sequence. So, the nth term for the given sequence is n^2 + n.
Well, darling, the nth term for the sequence 18, 12, 6, 0, -6 is -6n + 24. So, if you plug in n = 1, you get 18; n = 2 gives you 12, and so on. Just a little math magic for you to enjoy!
-4n + 24 #1 ; -4(1) +24 = 20 #2 ; -4(2) + 24 = 16 #3 ; =4(3) + 24 = 12
To find the nth term of the sequence -2, 3, 12, 24, 42, we can look at the differences between consecutive terms: 5, 9, 12, 18. The second differences are 4, 3, 6, suggesting a quadratic pattern. The nth term can be expressed as (a_n = an^2 + bn + c). By solving for a, b, and c using the terms, we find (a_n = \frac{1}{2}n^2 + \frac{3}{2}n - 2).
Give the simple formula for the nth term of the following arithmetic sequence. Your answer will be of the form an + b.12, 16, 20, 24, 28, ...
For {12, 15, 18} each term is the previous term plus 3; a general formula for the nth term is given by t(n) = 3n + 9. For {12, 24, 36} each term is the previous term plus 12; a general formula for the nth term is given by t(n) = 12n.
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
If you mean: 6 12 18 24 then the nth term is 6n
44
To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 4, then 8, then 12, then 16, and so on. This pattern suggests that the nth term can be represented by the formula n^2 + n, where n is the position of the term in the sequence. So, the nth term for the given sequence is n^2 + n.
Well, darling, the nth term for the sequence 18, 12, 6, 0, -6 is -6n + 24. So, if you plug in n = 1, you get 18; n = 2 gives you 12, and so on. Just a little math magic for you to enjoy!
To find the nth term of a sequence, we first need to identify the pattern or rule that governs the sequence. In this case, the sequence is decreasing by 6 each time. Therefore, the nth term can be represented by the formula: 18 - 6(n-1), where n is the position of the term in the sequence.
The nth term is (36 - 4n)
2n(n+1)
8 + 4n