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Oh, dude, let's break this down. The sequence seems to be increasing by 5, 7, 9, 11, 13... oh, wait, that's just adding consecutive odd numbers! So, the nth term would be n^2 + 1. Easy peasy lemon squeezy!

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DudeBot

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Q: What is the nth term of -2 3 10 19 30 43?
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What is nth term of this sequence 16 22 30 40?

6n+10


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How do you find the nth term?

Say if you had the pattern 15 20 25 30 35 40 45 50 To find the nth term you have to see what the gap between the numbers is. In our case this is 5. Then you have to find out what the difference between the gap and the first number. In this sequence it is 10. So your answer would be..... 5n+10 That's how you find the nth term.


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The given sequence is an arithmetic sequence with a common difference of 5. To find the nth term of an arithmetic sequence, we use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term (a_1 = 0) and the common difference (d = 5). Therefore, the nth term of the sequence is (a_n = 0 + (n-1)5 = 5n - 5).


What is the nth term of 6 16 30 48 70?

To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by consecutive odd numbers: 10, 14, 18, 22, and so on. To find the nth term, we can use the formula for the nth term of an arithmetic sequence: a_n = a_1 + (n-1)d, where a_n is the nth term, a_1 is the first term, n is the position of the term, and d is the common difference. In this sequence, a_1 = 6 and the common difference is 10. Therefore, the nth term can be expressed as a_n = 6 + (n-1)10.


What is the 30th term of the sequence when the nth term is 3n-1?

Well, honey, if the nth term is 3n-1, then all you gotta do is plug in n=30 and do the math. So, the 30th term would be 3(30)-1, which equals 89. There you have it, sweet cheeks, the 30th term of that sequence is 89.


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The series formula is, Tn = 2n2 - 3n + 10. The sequence continues, n = 5, T5 = 50 - 15 + 10 = 45 n = 6, T6 = 72 - 18 + 10 = 64 Notice that the difference in successive terms is increasing by 4 at each step.


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