Oh, dude, let's break this down. The sequence seems to be increasing by 5, 7, 9, 11, 13... oh, wait, that's just adding consecutive odd numbers! So, the nth term would be n^2 + 1. Easy peasy lemon squeezy!
The given sequence is 22, 14, 6, -2, -10. To find the nth term, we observe that the sequence decreases by 8, 8, 8, and so on. This indicates a linear relationship with a common difference of -8. The formula for the nth term can be expressed as ( a_n = 22 - 8(n - 1) ), which simplifies to ( a_n = 30 - 8n ).
To find the nth term of the pattern 10, 20, 40, 70, 110, 160, first observe the differences between consecutive terms: 10, 20, 30, 40, 50. These differences increase by 10 each time, suggesting a quadratic relationship. The nth term can be expressed as a quadratic equation: ( a_n = An^2 + Bn + C ). By solving a system of equations using the first three terms, we find ( a_n = 5n^2 + 5n ).
Wow you really can't spell.
The sequence given is -2, -9, -16, -23, -30. This is an arithmetic sequence where each term decreases by 7. The first term (a) is -2, and the common difference (d) is -7. The nth term can be expressed as ( a_n = -2 + (n-1)(-7) = -2 - 7(n-1) = -7n + 5 ).
The nth term of the sequence is 3n-8 and so the 30th term is 3*30 -8 = 82
6n+10
3 x 10(n-1)
Say if you had the pattern 15 20 25 30 35 40 45 50 To find the nth term you have to see what the gap between the numbers is. In our case this is 5. Then you have to find out what the difference between the gap and the first number. In this sequence it is 10. So your answer would be..... 5n+10 That's how you find the nth term.
Clearly here the nth term isn't n25.
90
The given sequence is 22, 14, 6, -2, -10. To find the nth term, we observe that the sequence decreases by 8, 8, 8, and so on. This indicates a linear relationship with a common difference of -8. The formula for the nth term can be expressed as ( a_n = 22 - 8(n - 1) ), which simplifies to ( a_n = 30 - 8n ).
This is an arithmetic progression. In general, If an A.P. has a first term 'a', and a common difference 'd' then the nth term is a + (n - 1)d. In the sequence shown in the question, the first term is 0 and the common difference is 5, therefore the nth term is, 0 + (n - 1)5. This can be rearranged to read : 5(n - 1) For example : the 7th term is 30 : 5(7 - 1) = 5 x 6 = 30.
I made a program that made the next 25is sequences after 16. It starts at #3 because 30 is #3 Here it is: 30 48 70 96 126 160 198 240 286 336 390 448 510 576 646 720 798 880 966 1056 1150 1248 1350 1456 1566 1680
Well, honey, if the nth term is 3n-1, then all you gotta do is plug in n=30 and do the math. So, the 30th term would be 3(30)-1, which equals 89. There you have it, sweet cheeks, the 30th term of that sequence is 89.
The nth term is 7n-5 and so the 6th term will be 37
The series formula is, Tn = 2n2 - 3n + 10. The sequence continues, n = 5, T5 = 50 - 15 + 10 = 45 n = 6, T6 = 72 - 18 + 10 = 64 Notice that the difference in successive terms is increasing by 4 at each step.
To find the nth term of the pattern 10, 20, 40, 70, 110, 160, first observe the differences between consecutive terms: 10, 20, 30, 40, 50. These differences increase by 10 each time, suggesting a quadratic relationship. The nth term can be expressed as a quadratic equation: ( a_n = An^2 + Bn + C ). By solving a system of equations using the first three terms, we find ( a_n = 5n^2 + 5n ).