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Without further restrictions it can be any of an infinite number of formulae.
For example, U{n} = (11n⁴ - 110x³ + 385x² - 518x + 176)/8 which gives the next term as 42.
However, if it is an ARITHMETIC SEQUENCE (as I suspect your teacher wants), then the nth term is found:
Common difference: (-3) - (-7) = 4
→ 0th term is -7 - 4 = -11
→ nth term U{n} = 4n - 11
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What is the nth term of 3 1 -1 -3 -5?
The nth term is: 5-2n
What is the nth term of 1 -3 -7 -11 and -15?
It is: nth term = 5-4n and so the next term will be -19
What is the nth term in 1 3 7 11 15?
If you mean -1 3 7 11 15 then the nth term is 4n-5 and so the next term will be 19
What is the nth term of 5 7 9?
2n+3. If 5 is the first term, then it is 2n + 3 (2×1 = 2 + 3 = 5 and 2×2 + 3 = 7)
What is the nth term for -1 3 -5 7 -9 11?
Un = (-1)n*(2n - 1)
What is the nth term of 3 1 -1 -3 -5?
The nth term is: 5-2n
What is the nth term of this sequence 3 5 7 9 11?
The nth term of the sequence is 2n + 1.
What is the nth term of 1 -3 -7 -11 and -15?
It is: nth term = 5-4n and so the next term will be -19
What is the nth term in 1 3 7 11 15?
If you mean -1 3 7 11 15 then the nth term is 4n-5 and so the next term will be 19
What is the nth term -5 -1 3 7?
Un = 4n - 9
The nth term for nĀ²-1?
5 first terms in n²+3
What is the nth term of the arithmetic sequence 7 5 3 1?
IT is A.P. Arithmetic progressionFormula to solven th term = First_term + ( n - 1)*difference_between_two_non=9first term=7difference_between_two_no = nth_term - (n-1)th_term = 5-7 = 3-5 =1-3 = -2nth term = 7+8*(-2) = -9Another Answer:-The nth term = 9-2n
What is the position to term rule for 1 5 9 13 17?
The nth term is 4n - 3
Nth term of the sequence 12 7 2 -3 .. I know what the next numbers in the sequence are but what is the expression for the nth term?
12 - 5(n-1)
What is the nth term of 5 7 9?
2n+3. If 5 is the first term, then it is 2n + 3 (2×1 = 2 + 3 = 5 and 2×2 + 3 = 7)
What is the nth term for -1 3 -5 7 -9 11?
Un = (-1)n*(2n - 1)
What is the nth term for 3 5 7 9?
This is an arithmetic sequence with initial term a = 3 and common difference d = 2. Using the nth term formula for arithmetic sequences an = a + (n - 1)d we get an = 3 + (n - 1)(2) = 2n - 2 + 3 = 2n + 1.
