To find the nth term of the quadratic sequence 3, 8, 15, 24, 35, we first identify the differences between the terms: 5, 7, 9, 11, which indicates a second difference of 2. This suggests the sequence can be represented by a quadratic formula of the form ( an^2 + bn + c ). By solving the equations formed using the first few terms, we find the nth term to be ( n^2 + 2n ). Thus, the nth term of the sequence is ( n^2 + 2n ).
To find the nth term of the sequence 5, 15, 29, 47, 69, we first determine the differences between consecutive terms: 10, 14, 18, and 22. The second differences are constant at 4, indicating that the nth term is a quadratic function. By fitting the quadratic formula ( an^2 + bn + c ) to the sequence, we find that the nth term is ( 2n^2 + 3n ). Thus, the nth term of the sequence is ( 2n^2 + 3n ).
To find the nth term in a quadratic sequence, first identify the first and second differences of the sequence. The second difference should be constant for a quadratic sequence. Use this constant to determine the leading coefficient of the quadratic equation, which is half of the second difference. Next, use the first term and the first difference to derive the complete quadratic formula in the form ( an^2 + bn + c ) by solving for coefficients ( a ), ( b ), and ( c ) using known terms of the sequence.
The given sequence is 1, 6, 13, 22, 33. To find the nth term, we can observe that the differences between consecutive terms are 5, 7, 9, and 11, which indicates that the sequence is quadratic. The nth term can be expressed as ( a_n = n^2 + n ), where ( a_n ) is the nth term of the sequence. Thus, the formula for the nth term is ( a_n = n^2 + n ).
The given sequence is -2, 1, 6, 13, 22, 33. To find the nth term, we observe that the differences between consecutive terms are increasing by 2 (3, 5, 7, 9). This indicates a quadratic pattern, and the nth term can be expressed as ( a_n = n^2 + n - 2 ). Thus, the nth term of the sequence is ( a_n = n^2 + n - 2 ).
To find the nth term of the sequence 4, 10, 18, 28, 40, we first identify the pattern in the differences between consecutive terms: 6, 8, 10, and 12. The second differences are constant at 2, indicating a quadratic sequence. The nth term can be expressed as ( a_n = n^2 + n + 2 ). Thus, the nth term of the sequence is ( n^2 + n + 2 ).
nth term is n squared plus three
94 and you skip it by 8's
To find the nth term of the sequence 5, 15, 29, 47, 69, we first determine the differences between consecutive terms: 10, 14, 18, and 22. The second differences are constant at 4, indicating that the nth term is a quadratic function. By fitting the quadratic formula ( an^2 + bn + c ) to the sequence, we find that the nth term is ( 2n^2 + 3n ). Thus, the nth term of the sequence is ( 2n^2 + 3n ).
nevermind i got it!!
To find the nth term in a quadratic sequence, first identify the first and second differences of the sequence. The second difference should be constant for a quadratic sequence. Use this constant to determine the leading coefficient of the quadratic equation, which is half of the second difference. Next, use the first term and the first difference to derive the complete quadratic formula in the form ( an^2 + bn + c ) by solving for coefficients ( a ), ( b ), and ( c ) using known terms of the sequence.
To find the nth term in this sequence, we first need to determine the pattern. The differences between consecutive terms are 5, 7, 9, and 11 respectively. These differences are increasing by 2 each time. This indicates that the sequence is following a quadratic pattern. The nth term for this sequence can be found using the formula for the nth term of a quadratic sequence, which is Tn = an^2 + bn + c.
The given sequence is 1, 6, 13, 22, 33. To find the nth term, we can observe that the differences between consecutive terms are 5, 7, 9, and 11, which indicates that the sequence is quadratic. The nth term can be expressed as ( a_n = n^2 + n ), where ( a_n ) is the nth term of the sequence. Thus, the formula for the nth term is ( a_n = n^2 + n ).
To find the nth term in a quadratic sequence, we first need to determine the pattern. In this case, the difference between consecutive terms is increasing by 3, 5, 7, 9, and so on. This indicates a quadratic sequence. To find the 9th term, we need to use the formula for the nth term of a quadratic sequence, which is given by: Tn = an^2 + bn + c. By plugging in n=9 and solving for the 9th term, we can find that the 9th term in this quadratic sequence is 74.
It is T(n) = n2 + 4*n + 2.
fsedaz sd
The given sequence is -2, 1, 6, 13, 22, 33. To find the nth term, we observe that the differences between consecutive terms are increasing by 2 (3, 5, 7, 9). This indicates a quadratic pattern, and the nth term can be expressed as ( a_n = n^2 + n - 2 ). Thus, the nth term of the sequence is ( a_n = n^2 + n - 2 ).
123456789 * * * * * The nth term is 3n