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Such numbers cannot be ordered in the manner suggested by the question because:

For every whole number there are integers, rational numbers, natural numbers, Irrational Numbers and real numbers that are bigger.

For every integer there are whole numbers, rational numbers, natural numbers, irrational numbers and real numbers that are bigger.

For every rational number there are whole numbers, integers, natural numbers, irrational numbers and real numbers that are bigger.

For every natural number there are whole numbers, integers, rational numbers, irrational numbers and real numbers that are bigger.

For every irrational number there are whole numbers, integers, rational numbers, natural numbers and real numbers that are bigger.

For every real number there are whole numbers, integers, rational numbers, natural numbers and irrational numbers that are bigger.

Each of these kinds of numbers form an infinite sets but the size of the sets is not the same. Georg Cantor showed that the cardinality of whole numbers, integers, rational numbers and natural number is the same order of infinity: aleph-null.

The cardinality of irrational numbers and real number is a bigger order of infinity: aleph-one.

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Q: What is the order from largest to smallest for whole number integers rational numbers natural number irrational numbers and real numbers?
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Related questions

What is comparing and ordering rational numbers?

Rational numbers are roots, decimals, fractions, and whole numbers. Bascially anything that can become a decimal. Irrational numbers are like pi. I'm pretty sure to be irrational, they have to repeat. Anyway, ordering them and comparing them means looking at them and seeing which is smallest and largest. Then you order them (smallest to largest or whatever it says).


What formula represents the largest of these integers if you are thinking of n consecutive positive integers and the smallest of which is m?

For x, which is the largest integer of nconsecutive positive integers of which the smallest is m:x = m + n - 1


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Start with the largest and end with the smallest


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Five times the smallest of three consecutive even integers is 10 more than twice the largest. find the integers?

5872345098234783904672083946728390752430689723409687298290843 theres your answer


Where can we find three consecutive even integers such that the largest is three times the smallest?

You've come to the right place. The integers are: 2, 4, and 6


What is the correct numerical order smallest to largest for the integers 34 5and 6?

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Find 3 consecutive integers such that twice the smallest is 12 more than the largest?

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Let the smallest integer be 2n, the next integer is 2n + 2, and the largest one is 2n + 4. Then, we have:2n + (2n + 2) = (2n + 4) + 164n + 2 = 2n + 202n = 18 the smallest integer2n + 2 = 18 + 2 = 20 the next one2n + 4 = 18 + 4 = 22 the largest integerCheck


The sum of three consecutive odd integers is -147 Find the largest of these three integers?

Divide the sum of the three consecutive odd integers by 3: -147 /3 = -49. The smallest of these integers will be two less than -49 and the largest will be two more than -49, so the three consecutive odd integers will be -47, -49, and -51.


What are the three consecutive even integers such the largest is three times the smallest?

x+(n+1)+3(n+2)= something then solve,