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They are (14, 15, 16).

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βˆ™ 2017-11-27 17:29:38
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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

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Q: Find 3 consecutive integers such that twice the smallest is 12 more than the largest?
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Five times the smallest of three consecutive even integers is 10 more than twice the largest. find the integers?

5872345098234783904672083946728390752430689723409687298290843 theres your answer


What are 3 consecutive integers such that twice the smallest is 12 more than the largest?

-- Call the three consecutive integers (x-1), x, and (x+1).-- Twice the smallest is 2(x-1) or (2x-2).-- 12 more than the largest is (x+1)+12 or (x+13).-- These are equal, so2x - 2 = x + 13Subtract 'x' from each side of the equation:x - 2 = 13Add 2 to each side:x = 15 .-- The smallest of the three numbers is (x-1) = 14.-- The three consecutive integers are 14, 15, and 16.-- Twice the smallest is 28.-- 28 is 12 more than 16.QED, man, QED !


The sum of three consecutive even integers is fourteen less than twice the smallest of these integers. What is the smallest and greatest integers?

three consecutives numbers: a = smallest a+2 a+4 14 less = -14 than twice the smallest = 2a so... a+a+2+a+4=-14+2a 3a+6=-14+2a 3a-2a=-14-6 a=-20 answer: smallest = -20 greatest = -16


Find three consecutive odd integers such that the sum of 7 times the smallest and twice the largest is -91?

98


Twice the smallest of three consecutive odd integers is seven more than the largest find the integers?

This equation works out to 2x = x + 11. This is because the three consecutive odd integers can be represented by x, x + 2, and x + 4. From the equation 2x - x = 11, so x = 11. Checking, 2 times 11 = 22 which is 7 more than 15. The three integers are 11, 13 and 15.


Twice the smallest of three consecutive integers is five more than the largestfind the integers?

7, 8, 9 Let x be the smallest of the three integers; thus, the integers are x, x+1, x+2. From the problem, we get: 2x=(x+2)+5=x+7 2x-x=7 x=7


If the largest of three consecutive even integers is multiplied by three the product is 2 less than twice the sum of the first two integers find the integers?

The answer would be 10 12 and 14... 14 x 3 = 42 and 2(10 + 12) = 44. So the product of the largest integer and three is two less than twice the sum of the lower integers.


Find three consecutive even integers such that if the largest integer is subtracted from four times the smallest the result is 8 more than twice the middle integer?

Suppose the middle integer is 2a. Then the smallest is 2a-2 and the biggest is 2a+2. 4 times the smallest is 8a-8 So largest subtracted from the smallest is (8a-8) - (2a+2) = 6a-10 So, 6a-10 = 2*2a = 4a so that 2a = 10 So the integers are 8, 10 and 12.


What are the integers of two consecutive integers which are eight more than twice their sum?

(x)(x+2)(x+4)


If sum of three consecutive even integers is fourteen less than twice the smallest of these integers. What is the smallest integer?

Suppose the smallest integer is A. The next two even numbers are A+2 and A+4. Using the information supplied we can form an equation: 2A - 14 = A + A+2 + A+4 Rearranging: 2A - 14 = 3A + 6 -20 = A So the three integers are -20, -18 and -16.


Find three consecutive even integers such that if the largest integer is subtracted from four times the smallest the result is 4 more than twice the middle integer?

If the largest integer is subtracted from four times the smallest, the result is 4 more than twice the middle integer. Let the smallest integer be x, then the others are x + 2 and x+ 4. Therefore 4x - (x + 4) = 2 (x + 2 ) + 4 Expanding, we get 4x -x -4 = 2x + 4 + 4 Gathering terms: x = 12 Thus the three integers are 12, 14 and 16.


Find two consecutive integers such that the larger is nine more than twice the smaller?

-10 and -11.

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