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Let the smallest integer be 2n, the next integer is 2n + 2, and the largest one is 2n + 4. Then, we have:

2n + (2n + 2) = (2n + 4) + 16

4n + 2 = 2n + 20

2n = 18 the smallest integer

2n + 2 = 18 + 2 = 20 the next one

2n + 4 = 18 + 4 = 22 the largest integer


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โˆ™ 2009-02-08 10:32:41
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Q: Find the largest of three consecutive even integers if the sum of the 2 smaller integers is 16 more than the largest integer What is the largest of the 3 integers?
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