Let the smallest integer be 2n, the next integer is 2n + 2, and the largest one is 2n + 4. Then, we have:
2n + (2n + 2) = (2n + 4) + 16
4n + 2 = 2n + 20
2n = 18 the smallest integer
2n + 2 = 18 + 2 = 20 the next one
2n + 4 = 18 + 4 = 22 the largest integer
Check
-1
The smaller integer is 17.
The two integers are 6 and 7.
6+7=13 and 6 and 7 are consecutive. 6 is the smaller integer so answer is 6
The larger integer is 30. The smaller is 28.
The numbers are 9 and 10.
The sum is four.
x+3 and x+4 would be consecutive integers.
13 and 12 are the two integers that have the product of 156 and 12 is the smaller of the two.
There can be no such integers: a smaller integer cannot be 5 times the larger number.
5 and 6
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.