Ther is a 50% chance you will have two p alleles
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0.58
This is a Hardy Weindburg situation P represents the percentage of the population that has a dominant allele... now there can only be two alleles one is dominant and one is recessive... q is the recessive allele This means that p+q=1 and so q has to be equal to 0.32 If you do the square of p (p^2) then that gives you the number of people who are homozygous dominant If you do the square of q (q^2) then that gives you the number of people who are homozygous recessive If you do 2*(p*q) then that will give you the number of people who are heterozygous Hope this helps...
If A and B are two events then P(A or B) = P(A) + P(B) - P(A and B)
just do 163 divided by 14 simple as that. :P :P :P :P :P
The expression that represents two times the sum of p and 8 is 2(p + 8).