Ther is a 50% chance you will have two p alleles
0.58
This is a Hardy Weindburg situation P represents the percentage of the population that has a dominant allele... now there can only be two alleles one is dominant and one is recessive... q is the recessive allele This means that p+q=1 and so q has to be equal to 0.32 If you do the square of p (p^2) then that gives you the number of people who are homozygous dominant If you do the square of q (q^2) then that gives you the number of people who are homozygous recessive If you do 2*(p*q) then that will give you the number of people who are heterozygous Hope this helps...
If A and B are two events then P(A or B) = P(A) + P(B) - P(A and B)
just do 163 divided by 14 simple as that. :P :P :P :P :P
The expression that represents two times the sum of p and 8 is 2(p + 8).
i love you to all of the colores
0.11
.93
0.93
In a population with two alleles for a trait, the frequencies of the alleles must add up to 1. If the frequency of allele p is 0.68, then the frequency of allele q can be calculated as q = 1 - p. Therefore, q = 1 - 0.68 = 0.32.
0.78
0.58
.78 (Apex)
0.11
Different alleles for a trait are known as gene variants. For example, two different alleles for the gene that determines flower color in pea plants are purple (P) and white (p). When an individual has two different alleles for a trait, it is known as heterozygous.
0.65
0.58