i love you to all of the colores
If the event in question is A and the probability of A occurring is P(A), then the probability of A not occurring is P(A')=1-P(A).
This problem is the type of the probability of A and the probability of B. These events are independent. P(A) and P(B) = P(A) * P(B). In this case these two probabilities are equal; the probability of a king is 4/52. So, the probability of draw king, replace and draw king is 4/52 * 4/52 = 0.00592.
Given two events, A and B, the conditional probability rule states that P(A and B) = P(A given that B has occurred)*P(B) If A and B are independent, then the occurrence (or not) of B makes no difference to the probability of A happening. So that P(A given that B has occurred) = P(A) and therefore, you get P(A and B) = P(A)*P(B)
A union probability is denoted by P(X or Y), where X and Y are two events. P(X or Y) is the probability that X will occur or that Y will occur or that both X and Y will occur. The probability of a person wearing glasses or having blond hair is an example of union probability. All people wearing glasses are included in the union, along with all blondes and all blond people who wear glasses. According to Professor Franz Kurfess of California Polytechnic State University, San Luis Obispo, union probability of two independent events A and B can be denoted as: P(A ∪ B) = P(A) + P(B) - P(A ∩ B) = P(A) + P(B) - P(A) * P (B)
No. It depends on the probability of success, p. If p < 0.5 the distribution is positively skewed.No. It depends on the probability of success, p. If p < 0.5 the distribution is positively skewed.No. It depends on the probability of success, p. If p < 0.5 the distribution is positively skewed.No. It depends on the probability of success, p. If p < 0.5 the distribution is positively skewed.
Ther is a 50% chance you will have two p alleles
The chances of inheriting two p alleles depend on the genetic makeup of the parents. If both parents are heterozygous for the p allele (Pp), there is a 25% chance their offspring will inherit two p alleles (pp). If one parent is homozygous dominant (PP) and the other is homozygous recessive (pp), the offspring will not inherit two p alleles. Thus, the inheritance pattern is influenced by the genotypes of the parents.
0.11
In a trait with two alleles represented by ( p ) and ( q ), the sum of the frequencies of the alleles must equal 1. If ( p = 0.35 ), then ( q ) can be calculated as ( q = 1 - p ). Therefore, ( q = 1 - 0.35 = 0.65 ).
In a trait with two alleles represented by p and q, the sum of the frequencies of the alleles must equal 1. If p equals 0.35, then q can be calculated as q = 1 - p. Therefore, q = 1 - 0.35, which equals 0.65.
.93
0.93
In a population with two alleles for a trait, the frequencies of the alleles must add up to 1. If the frequency of allele p is 0.68, then the frequency of allele q can be calculated as q = 1 - p. Therefore, q = 1 - 0.68 = 0.32.
0.78
0.58
.78 (Apex)
0.11