There are many different rules that will generate any given sequence.
One option is t(n) = n3 - 3n2 + 8n + 1 for n = 1, 2, 3, ...
another is t(n) = 3*2n + 1 for n = 1, 2, 3, ...
Which one of these depends on whether the next term is 157 (cubic) or 97 (power).
61
81
36.7525% off of 49= 25% discount applied to 49= 49 - (25% * 49)= 49 - (0.25 * 49)= 49 - 12.25= 36.75
49 over 25 as a decimal = 1.9649/25= 49 ÷ 25= 1.96 in decimal
factors of : 25 = 1, 5, 25 49 = 1, 7, 49
61
t(n) = n2
81
36.7525% off of 49= 25% discount applied to 49= 49 - (25% * 49)= 49 - (0.25 * 49)= 49 - 12.25= 36.75
Assuming the sequence does not merely skip from 13 to 49, and instead carries on in the same pattern, the sequence proceeds thus:1, 5, 9, 13, 17, 21, 25, 29, 33, 37, 41, 45, 49.This is thirteen terms. The formula for finding these terms is 4x-3.
You have to find a pattern in the numbers, and exclude the one that messes up the pattern.
Reducing squares 100 = 10² 81 = 9² 64 = 8² 49 = 7² 36 = 6² so next is 25 = 5² ---------------------------------- For the given pattern the nth term (n = 1 to 5) is given by: t(n) = n² - 22n + 121
The next number will be 25 because 5 times 5 = 25
49 over 25 as a decimal = 1.9649/25= 49 ÷ 25= 1.96 in decimal
factors of : 25 = 1, 5, 25 49 = 1, 7, 49
Reducing squares 9 x 9 = 81 8 x 8 = 64 7 x 7 = 49 6 x 6 = 36 so next would be 5 x 5 = 25
49 - 25 = 24