There are many different rules that will generate any given sequence.
One option is t(n) = n3 - 3n2 + 8n + 1 for n = 1, 2, 3, ...
another is t(n) = 3*2n + 1 for n = 1, 2, 3, ...
Which one of these depends on whether the next term is 157 (cubic) or 97 (power).
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∙ 12y ago61
81
36.7525% off of 49= 25% discount applied to 49= 49 - (25% * 49)= 49 - (0.25 * 49)= 49 - 12.25= 36.75
49 over 25 as a decimal = 1.9649/25= 49 ÷ 25= 1.96 in decimal
factors of : 25 = 1, 5, 25 49 = 1, 7, 49
61
t(n) = n2
You have to find a pattern in the numbers, and exclude the one that messes up the pattern.
Assuming the sequence does not merely skip from 13 to 49, and instead carries on in the same pattern, the sequence proceeds thus:1, 5, 9, 13, 17, 21, 25, 29, 33, 37, 41, 45, 49.This is thirteen terms. The formula for finding these terms is 4x-3.
Reducing squares 100 = 10² 81 = 9² 64 = 8² 49 = 7² 36 = 6² so next is 25 = 5² ---------------------------------- For the given pattern the nth term (n = 1 to 5) is given by: t(n) = n² - 22n + 121
81
36.7525% off of 49= 25% discount applied to 49= 49 - (25% * 49)= 49 - (0.25 * 49)= 49 - 12.25= 36.75
Reducing squares 9 x 9 = 81 8 x 8 = 64 7 x 7 = 49 6 x 6 = 36 so next would be 5 x 5 = 25
The next number will be 25 because 5 times 5 = 25
49 over 25 as a decimal = 1.9649/25= 49 ÷ 25= 1.96 in decimal
The pattern is the squared numbers with the digits reversed. 92 = 81 → 18 82 = 64 → 46 72 = 49 → 94 62 = 36 → 63 52 = 25 → 52 42 = 16 → 61
factors of : 25 = 1, 5, 25 49 = 1, 7, 49