If you know a side length, s, the perimeter is 8 s
If you know the circum radius, r, (the distance from the center to a vertex) , the perimeter is
p = 8 r sqrt(2 - sqrt(2)) (approx 6.12 r)
If you know the apothem, a, (the distance from the center to the middle of a side),
p = 16 a sqrt(2-sqrt(2))/sqrt(sqrt(2)+2) (approx 6.63 a)
If the octagon is not regular, the perimeter could have any value greater than 18 inches. If it is regular, then the perimeter is 8*18 = 144 inches.
' 8a ' is.
About 391.1 units2
The perimeter of an octagon is 64 only if it is a regular octagon and the length of one side is 8. An irregular octagon may or may not have a perimeter of 64 (whatever units of measure you choose to use) depending on what the lengths of the individual sides are.
You say these things to yourself: -- "The perimeter is the distance all the way around the octagon." -- "The octagon has eight sides." -- "So, if it's a 'regular' octagon, then all the sides are the same length, and each side must be 1/8 of the perimeter." -- If it's not a 'regular' octagon, then it has some longer sides and some shorter ones, and the perimeter doesn't help me find the lengths of the sides.
The perimeter of a octagon is the sum of all its sides.
The perimeter is 56.
If it's a regular octagon, the perimeter is 8 times the length of one side.
If a regular octagon has a perimeter of 40cm, then each side is 5 cm.
The perimeter is 72.
If the octagon is not regular, the perimeter could have any value greater than 18 inches. If it is regular, then the perimeter is 8*18 = 144 inches.
' 8a ' is.
I'm not sure what mile metres are, but a regular octagon with a side of 70 whatevers will have a perimeter of 560 whatevers.
Perimeter = 8*7 = 56 cm
Perimeter = 8*15 = 120 cm
pentagon
About 391.1 units2