It is the sum of its 4 sides
The area of a lot is not enough information to determine its perimeter. The most compact perimeter is approx 740 feet, which is attained by a circular lot. Consider the following rectangular plots, each is of area 1 acre: 100 ft * 435.6ft : perimeter = 1071.2 ft 10 ft * 4356 ft : perimeter = 8732 ft 1 ft * 4356 ft : perimeter = 87122 ft 0.1 ft * 43560 ft : perimeter = 871200.2 ft ... 0.000001 ft * 43,560,000,000 ft : perimeter = 87,120,000,000 ft (approx) = 16,500,000 miles. There is virtually no limit to how much the first dimension can be reduced and the perimeter increased.
just find the perimeter
perimeter = 2l + 2w l = 9 yards w = 12 yards perimeter = 2*9 yards + 2*12 yards = 18 + 24 = 42 yards
The perimeter of a rectangle is 2*(width + depth) So 500 = 2*(104 + depth) 250 = 104 + depth depth = 146 feet
The dimensions of the rectangular lot are: 30m by 15m
By halving its perimeter and using the quadratic equation formula.
The perimeter is: 5.5+3.25+5.5+3.25 = 17.5 m
It is the sum of its 4 sides
The area of a lot is not enough information to determine its perimeter. The most compact perimeter is approx 740 feet, which is attained by a circular lot. Consider the following rectangular plots, each is of area 1 acre: 100 ft * 435.6ft : perimeter = 1071.2 ft 10 ft * 4356 ft : perimeter = 8732 ft 1 ft * 4356 ft : perimeter = 87122 ft 0.1 ft * 43560 ft : perimeter = 871200.2 ft ... 0.000001 ft * 43,560,000,000 ft : perimeter = 87,120,000,000 ft (approx) = 16,500,000 miles. There is virtually no limit to how much the first dimension can be reduced and the perimeter increased.
The length of the rectangle is 27 meters and the width is 19 meters.
just find the perimeter
perimeter = 2l + 2w l = 9 yards w = 12 yards perimeter = 2*9 yards + 2*12 yards = 18 + 24 = 42 yards
The perimeter of a rectangle is 2*(width + depth) So 500 = 2*(104 + depth) 250 = 104 + depth depth = 146 feet
Calculate the perimeter then multiply by 3.5. Don't want to give you the full answer.
2(x + y) = 156 x = 2y Here x = length of rectangle and y = width
It is not correct to say that 14 lineal metres is the length of the plot. The length of the plot is 4 m, the width is 3 m and the perimeter is 14 m. You can see how absurd your assertion becomes if the plot is a shape other than rectangular, for example, triangular or circular.