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Pi over 4 radians is equivalent to 45 degrees. This is calculated by converting radians to degrees using the formula: degrees = radians × (180/π). Therefore, π/4 × (180/π) = 45 degrees.

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5mo ago

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Does pi over 4 equal 45 degrees?

pi/4 radians = 45 degrees. 2pi radians = 360 degrees pi radians = 180 degrees pi/2 radians = 90 degrees pi/4 radians = 45 degrees pi/3 radians = 60 degrees. et seq.,


How many degrees is pi over three?

pi over three is 60 degrees.


What is 240 degrees in terms of pi?

pi = 180 degrees 240 degrees = 240/180 time pi = 4 pi/3


What kind of angle is 4 pi divided by 5?

pi = 180 degrees pi / 2 = 90 degrees 2 pi = 360 degrees so pi / 5 = 180 / 5 = 36 36 x 4 = 144 degrees a 144 degree angle is obtuse


Are radiants converted to degrees by deviding by 180 degrees?

(3pi/4) * (180/pi) = 135 degrees ============ pi cancels, top and bottom, multiply 180 by 3 and divide by 4


What is Tan pi over 4?

tangent of pi/4 = 1


What is sin of pi over 12 on a radian circle?

The sine of (\frac{\pi}{12}) radians (which is equivalent to 15 degrees) can be calculated using the sine subtraction formula: (\sin(a - b) = \sin a \cos b - \cos a \sin b). By letting (a = \frac{\pi}{4}) (45 degrees) and (b = \frac{\pi}{3}) (60 degrees), we find that (\sin\left(\frac{\pi}{12}\right) = \sin\left(\frac{\pi}{4} - \frac{\pi}{3}\right) = \sin\frac{\pi}{4} \cos\frac{\pi}{3} - \cos\frac{\pi}{4} \sin\frac{\pi}{3}). This evaluates to (\frac{\sqrt{2}}{2} \cdot \frac{1}{2} - \frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} = \frac{\sqrt{2}}{4} - \frac{\sqrt{6}}{4} = \frac{\sqrt{2} - \sqrt{6}}{4}).


What is pi over 12 on a radian circle?

pi/12 = (pi/12)/(2pi) = 1/24 of a circle ( = 15 degrees).


What is the measure of a angle with 45 degrees?

It is pi/4 radians.


What is pi divided by 4?

45 degrees or 0.785398163. The first part is pi radians divided by 4, not quite the same thing.


Tan what equals 1?

45 degrees (+/- 180k degrees for any integer k) or pi/4 radians (+/- pi*k radians for any integer k).


What is the exact value of the expression cos 7pi over 12 cos pi over 6 -sin 7pi over 12 sin pi over 6?

cos(a)cos(b)-sin(a)sin(b)=cos(a+b) a=7pi/12 and b=pi/6 a+b = 7pi/12 + pi/6 = 7pi/12 + 2pi/12 = 9pi/12 We want to find cos(9pi/12) cos(9pi/12) = cos(3pi/4) cos(3pi/4)= cos(pi-pi/4) cos(pi)cos(pi/4)-sin(pi)sin(pi/4) cos(pi)=-1 sin(pi)=0 cos(pi/4) = √2/2 sin(pi/4) =√2/2 cos(pi)cos(pi/4)-sin(pi)sin(pi/4) = - cos(pi/4) = -√2/2