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What is the point of intersection of the line y equals 2x plus 5 over 4 with the curve y squared equals 10x?
Point of intersection: (5/8, 5/2)
Square both sides of the first equation and merge it with the second equation to form a quadratic equation:-
4x2-5x+25/16 = 0
Solving the above using the quadratic equation formula gives x as having two poitive roots of 5/8 and substituting this into the linear equation gives y a value of 5/2.
What else can I help you with?
What is the point of intersection of the parabolas of y equals 3x squared plus 10x plus 11 and y equals 2 -2x -x squared?
They intersect at the point of: (-3/2, 11/4)
What are the point of intersection of x is equal to y squared plus 2y?
You need two, or more, curves for points of intersection.
What is the point of cotact when the line y equals 2x plus 5 over 4 meets the curve y squared equals 10xa?
If you mean a line of y = 2x+5/4 and a curve of y^2 = 10x Then it works out that the line touches the curve at: (5/8, 5/2)
X equals 1 and y equals 6 what is the point of intersection?
1,6
What is the intersection point of the lines 2x plus y equals 2 and -3x-2y equals -6?
The intersection is (-2, 6)
At what point is the line of y equals x -4 tangent to the curve of x squared plus y squared equals 8?
(2, -2)
What is the point of intersection of the parabolas of y equals 3x squared plus 10x plus 11 and y equals 2 -2x -x squared?
They intersect at the point of: (-3/2, 11/4)
What is the value of k when y equals 3x plus 1 is a line tangent to the curve of x squared plus y squared equals k hence finding the point of contact of the line to the curve?
It is (-0.3, 0.1)
What is the value of c when y equals x plus c is a tangent to the curve y equals 3 -x -5x squared hence finding the point of contact of the line with the curve showing work?
-2
What are the point of intersection of x is equal to y squared plus 2y?
You need two, or more, curves for points of intersection.
What is the point of cotact when the line y equals 2x plus 5 over 4 meets the curve y squared equals 10xa?
If you mean a line of y = 2x+5/4 and a curve of y^2 = 10x Then it works out that the line touches the curve at: (5/8, 5/2)
X equals 1 and y equals 6 what is the point of intersection?
1,6
What is the intersection point of the lines 2x plus y equals 2 and -3x-2y equals -6?
The intersection is (-2, 6)
What is the point of intersection of the lines 6y equals -x -25 and 6x plus 20.5 -y equals 0?
It works out that the point of intersection is at (-4, -3.5) on the Cartesian plane.
Explain quantitatively why the maximum power transfer curve is not symmetrical about the point where the source resistance equals load resistance?
when we look at the curve ,, we can see that before the peak point curve has greater slope as compared to the slope after the peak point .. the reason is PL is given as I^2RL ,,, current is a squared term here . before peak point current is greater so overall change in power is much greater but after peak point RL is greater and current is less now the load resistance is not a squared term... so slope will be less. therefore the curve is not symetrical
What is the point of contact when the line y equals 2x plus 1.25 touches the curve y squared equals 10x?
Combine the equations together and using the quadratic equation formula it works out that the point of contact is at (5/8, 5/2)
What point does the normal intersect?
The normal intersects a curve at a right angle, forming a perpendicular line to the tangent of the curve at that point. This intersection is crucial for determining the rate of change or slope of a function at a specific point.
