It is 4/8 = 1/2
7
The spinner has five equal sections marked 1 through 5, with the even numbers being 2 and 4. There are 2 favorable outcomes (landing on an even number) out of a total of 5 possible outcomes. Therefore, the probability of landing on an even number is ( \frac{2}{5} ) or 40%.
1/2 * 1/2 = 1/4 1/2= probability of landing an even number 1/2 = probability of landing a heads
To determine the odds of a spinner not landing on an even number, you first need to know the total number of sections and how many of those sections are even numbers. If the spinner has, for example, 8 sections numbered from 1 to 8, there are 4 even numbers (2, 4, 6, 8) and 4 odd numbers (1, 3, 5, 7). In this case, the odds of not landing on an even number would be 4 out of 8, or 50%. The specific odds can change based on the total number of sections and the distribution of even and odd numbers.
Coin landing of heads = 1/2 (either heads or tails) Dice landing on even number = 1/2 (no matter how many faces there are on the dice unless the number of faces is odd, 6 sided=3 even sides/6)
7
1/2
9
If I have understood the question correctly, the answer is 1/2.
The probability is 3/7.
It depends on the spinner: how many sides it has, whether or not they are the same size, what numbers are on the spinner.
1/2 * 1/2 = 1/4 1/2= probability of landing an even number 1/2 = probability of landing a heads
17 out of 21
It depends on how many points there are that the spinner can land on. If there are 8, for example, the probability would be 8/16, or 1/2...
I believe it's 4/8 or 1/2 and the probability of the even number is 4/8 also.
3/6=1/2 on a number cube it depends on how many sides of a spinner there are if its an even number always 1/2 if its an odd number of sides it cant be simplified
5/12 If it's wrong don't mind me, i'm not even in middle school yet i'm just smart