Q: What is the probability that the spinner will land on an even number?

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It is the proportion of the spinner's perimeter that is occupied by the section (or sections) with a value of 1.

It depends on how many other positions are on the spinner. The question, as asked, cannot be answered. Please restate the question, giving also the total number of positions on the spinner.

4 of 4

Zero. Since coins land on Heads or Tails and not numbers.

Presuming that the spinner and the number cube are both "fair", then no - spinning the spinner and tossing the six-sided number cube are called statistically independent events. They do not influence each other, and it does not matter which order the events occur in.

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It depends on how many points there are that the spinner can land on. If there are 8, for example, the probability would be 8/16, or 1/2...

I believe it's 4/8 or 1/2 and the probability of the even number is 4/8 also.

The probability that the spinner will land on six depends on how many numbers are on the spinner. If the spinner is only 1 through 6, then there is a 16.67% probability that the spinner will land on six with each spin.

It is the proportion of the spinner's perimeter that is occupied by the section (or sections) with a value of 1.

The answer depends on the shape of the spinner and the numbers on it.

Assuming the spinner has only a finite number of colours, the probability is 0. If there are n colours then on the (n+1)th spin the spinner cannot land on a different colour.

That would depend on how many numbers are on the spinner and the cube. The more numbers there are, the less likely it is that they would both land an any given number.

It depends on how many other positions are on the spinner. The question, as asked, cannot be answered. Please restate the question, giving also the total number of positions on the spinner.

4 of 4

Assuming that the colors are balanced, the probability is 1 in 5.

The answer depends on the number of sides on the spinner and how they are numbered.

The probability of landing on black twice on a spinner with white, black, and striped sections is (1/3)^2 = 1/9. This is because there is a 1/3 chance of landing on black on each spin, and the spins are independent events.