Probability of a spinner of 20 landing on 5 is 1/20.
In a spinner numbered from 1 to 10, the multiples of 5 are 5 and 10. There are 2 favorable outcomes (5 and 10) out of a total of 10 possible outcomes. Therefore, the probability of landing on a multiple of 5 is 2 out of 10, which simplifies to 1/5 or 0.2. Thus, the probability is 20%.
To determine how many times you would expect to land on 3 after spinning the spinner 20 times, you need to know the probability of landing on 3 in a single spin. If the spinner has an equal number of sections, you can find the probability by dividing the number of sections that include 3 by the total number of sections. Multiply that probability by 20 to get the expected number of times landing on 3. For example, if the spinner has 4 equal sections, the expected number would be (20 \times \frac{1}{4} = 5).
The answer depends on the characteristics of the spinner.The answer depends on the characteristics of the spinner.The answer depends on the characteristics of the spinner.The answer depends on the characteristics of the spinner.
The spinner has five equal sections marked 1 through 5, with the even numbers being 2 and 4. There are 2 favorable outcomes (landing on an even number) out of a total of 5 possible outcomes. Therefore, the probability of landing on an even number is ( \frac{2}{5} ) or 40%.
The probability is(the total number of numbers on the spinner minus 5)/(the total number of numbers on the spinner)Another way to express the same probability is1 - 5/(the total number of numbers on the spinner)
In a spinner numbered from 1 to 10, the multiples of 5 are 5 and 10. There are 2 favorable outcomes (5 and 10) out of a total of 10 possible outcomes. Therefore, the probability of landing on a multiple of 5 is 2 out of 10, which simplifies to 1/5 or 0.2. Thus, the probability is 20%.
The probability is 5/9.
The answer depends on the characteristics of the spinner.The answer depends on the characteristics of the spinner.The answer depends on the characteristics of the spinner.The answer depends on the characteristics of the spinner.
9
The spinner has five equal sections marked 1 through 5, with the even numbers being 2 and 4. There are 2 favorable outcomes (landing on an even number) out of a total of 5 possible outcomes. Therefore, the probability of landing on an even number is ( \frac{2}{5} ) or 40%.
2:5
You have a 1/9 chance of landing a 2 on the first spin and a 1/9 chance of landing 5 on the second, so the chances of landing on a 2 then a 5 should be (1/9)*(1/9) = 1/81
The probability is(the total number of numbers on the spinner minus 5)/(the total number of numbers on the spinner)Another way to express the same probability is1 - 5/(the total number of numbers on the spinner)
The answer depends on the shape of the spinner and the numbers on it.
If the lines between the sections had no width: 20% of Landing on 1, 20% on 2, 20% on 3, 20% on 4 and 20% on 5.
Assuming that the colors are balanced, the probability is 1 in 5.
Well it would really depend on how many sections there are in the spinner and how many 3's and 5's there are.