As a coin has two sides, the odds are always 50-50.
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The probability of NOT getting heads is (1/2)4=1/16 Therefore the probability of getting heads is 1-1/16=15/16
The probability of rolling a 2 on a die before flipping a heads on a coin is 1 in 12. The probability of rolling a 2 is 1 in 6. The probability of flipping heads is 1 in 2. Since these are sequentially unrelated events, you simply multiply the probabilities together.
None, since that would imply that in 18 cases the coin did not show heads or tails!
The probability of tossing a coin and getting heads is 0.5
Your question is a bit difficult to understand. I will rephrase it as follows: What is the probability of getting a head if a coin is flipped once? p = 0.5 What is the probability of getting 2 heads if a coin is flipped twice = The possible events are HT, TH, HH, TT amd all are equally likely. So the probability of HH is 0.25. What is the probability of getting at least on head if the coin is flipped twice. Of the possible events listed above, HT, TH and HH would satisfy the condition of one or more heads, so the probability is 3 x 0.25 = 0.75 or 3/4. Also, since the probability of TT is 0.25, and the probability of all events must sum to 1, then we calculate the probability of one or more heads to be 1-0.25 = 0.75