To get four Aces it is necessary to draw several cards. There is no information on how many cards are drawn. Whether or not they are drawn randomly.
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48/52 or 92% chance of NOT getting an ace.
The probability of drawing a Ace from a standard deck of 52 cards if one Ace is missing is 3 in 51, or about 0.05882. If the missing card is not an Ace, then the probability is 4 in 51, or about 0.07843.
Let A= getting an ace the first timeand B= getting an ace the secondWe are looking to for the probaliity of getting A and B that is P(A and B)We know P(A and B) = P(A) . P(B|A)= (4/52) . (3/51) = 1/122 = .00452NOTE that P(B|A) is the conditional probability of getting an ace the second time given that you got an ace the first time.
Probability not ace is 1 minus probability of an ace which is 4/52. So, 1 - 4/52 is 48/52 or 12/13.
Probability of not drawing an ace equals one minus the probability of drawing an ace. The probability of drawing an ace is 4/52 or 1/13. So the probability of not drawing an ace on one draw is 1 - 1/13 or 12/13 or 0.9231 (92.31%).