In the sample space [1,20], there are 8 prime numbers, [2,3,5,7,11,13,17,19]. The probability, then, of randomly choosing a prime number in the sample space [1,20] is (8 in 20), or (2 in 5), or 0.4. The probability of choosing two of them is (8 in 20) times (7 in 19) which is (56 in 1064) or (7 in 133) or about 0.05263.
In this problem, the total number of possibilities is 20, so n = 20.The set of prime numbers from 1 to 20 = {2, 3, 5, 7, 11, 13, 17, 19}, so f = 8Probability = f/n = 8/20 = 0.4.You have a 2 in 5 chance of choosing a prime number from 1 to 20.
It depends on what variable the probability ratio was for! The random variable could have been the number of heads minus the number of tails, for example.
The result of tossing the coin would not affect which number was selected. So we say that these two events are independent. We can therefore assess the probability of each of them separately and then multiply the two probabilities together for a final result. Probability of getting tails: 1/2 (since there is one way of getting heads out of two possibilities) Probability of getting zero: 1/10 (since there is one way of getting zero out of ten possibilities) Overall probability: 1/2 x 1/20 = 1/20
The first prime after 20 is 23.
There are 20 numbers from 20 through 39, and 4 of them are prime (23, 29, 31, 37), the probability is 4 in 20 or 0.20.
The probability is 8/20.
In the sample space [1,20], there are 8 prime numbers, [2,3,5,7,11,13,17,19]. The probability, then, of randomly choosing a prime number in the sample space [1,20] is (8 in 20), or (2 in 5), or 0.4. The probability of choosing two of them is (8 in 20) times (7 in 19) which is (56 in 1064) or (7 in 133) or about 0.05263.
There are eight prime numbers between 1 and 20.2, 3, 5, 7, 11, 13, 17, 19If you randomly choose in number then you have an 8 in 20 chance of selecting a prime.The probability is selecting a prime number is 8/20 or 0.4
There are 8 out of 20 numbers that are prime, so 8/20, or 2/5.
There are 12 composite (and 8 primes) in the first twenty whole numbers. So the probability of randomly choosing a non-prime is 12/20 or 60%.
1 out of 20 this is because there are 20 numbers in total, and there is only one 7 in there. (Assuming that there is the same probability for each number to be chosen, and that 17 is excluded as an affirmative outcome)
In this problem, the total number of possibilities is 20, so n = 20.The set of prime numbers from 1 to 20 = {2, 3, 5, 7, 11, 13, 17, 19}, so f = 8Probability = f/n = 8/20 = 0.4.You have a 2 in 5 chance of choosing a prime number from 1 to 20.
There are 8 prime numbers (2, 3, 5, 7, 11, 13, 17, 19) between 1 and 20, the rest are comp. P(prime then comp) = (8/20) * (11/20) = .22 There is a 22% chance you will draw a prime number followed by a composite number. ...maybe...
It depends on what variable the probability ratio was for! The random variable could have been the number of heads minus the number of tails, for example.
No, a probability must needs be a number between 0 and 1.20% might be a probability, though - since that is equivalent to 0.2.
The result of tossing the coin would not affect which number was selected. So we say that these two events are independent. We can therefore assess the probability of each of them separately and then multiply the two probabilities together for a final result. Probability of getting tails: 1/2 (since there is one way of getting heads out of two possibilities) Probability of getting zero: 1/10 (since there is one way of getting zero out of ten possibilities) Overall probability: 1/2 x 1/20 = 1/20