There is no simple answer to this question because the genders of children depend on the parents genes and age and so are not independent events. Also, the probabilities of the two genders are not equal. Further, some of the children may be identical twins or triplets.
Assuming, however, that the genders are independent, the answer is 0.3872, approx.
6 out of 9.
I wouldn't say it's very probable. My neighbor has three children and they're all boys. It just depends on the mother and father.
This is a Binomial Probability; p=0.5, n=10 & x=7. Since you want the probability of exactly 7, in the related link calculator, after placing in the above values, P(x=7) = 0.1172 or 11.72%.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability that all three children are boys is approx 0.1381
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of the other two being boys is 0.2672.
6 out of 9.
4/16 or 0.2 or 25%
In a family with four children, the probability of having four boys is 1 in 16.
I wouldn't say it's very probable. My neighbor has three children and they're all boys. It just depends on the mother and father.
The answer depends on whether the children are picked at random. If they were selected from inside a girls' school the probability should be quite close to 0. Likewise, if the children were picked inside a boys' school. If six children are picked at random from a large group of children with an equal number of boys and girls, then the answer is 6C2*(1/2)6 = 15/32 = 0.47, approx.
This is a Binomial Probability; p=0.5, n=10 & x=7. Since you want the probability of exactly 7, in the related link calculator, after placing in the above values, P(x=7) = 0.1172 or 11.72%.
1/8
Assuming boys are equally as likely as girls, 125 boys would be expected. The probability of getting 140 or fewer boys is approximately 97.51%
Probability equals the number of ways an event can occur divided by the total number of events. The total number of events is (b=boy, g=girl) is bb, bg, gb, gg. The probability is then 1/4.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability that all three children are boys is approx 0.1381
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of the other two being boys is 0.2672.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of 3 boys out of 13 is 0.0273.