It is 1/18.
First probability of getting 2 is one in six: 1/6probability of getting no greater than 4 is two chances in six (must be a 5 or 6): 2/6=1/3so probability = 1/6*1/3= 1/18.
13/204
The probability is 1/2 because the second outcome has no affect on the first outcome.
No, it's not a probability since it's not set in terms of ratio of two values, such that the second value is greater than the first. For instance: 1 to 2 or 1 / 2. Also, probability is never negative.
What is the probability of rolling a 6 the first time and a 1 the second time
13/204
First probability of getting 2 is one in six: 1/6probability of getting no greater than 4 is two chances in six (must be a 5 or 6): 2/6=1/3so probability = 1/6*1/3= 1/18.
The probability is 1/2 because the second outcome has no affect on the first outcome.
1 in 2 to get tails on first toss 1 in 2 to get heads on second toss To get tails on first toss and heads on second toss, probability is 1/2 x 1/2 = 1 in 4
No, it's not a probability since it's not set in terms of ratio of two values, such that the second value is greater than the first. For instance: 1 to 2 or 1 / 2. Also, probability is never negative.
The first dice can show any number. However the second dice has a 1 in 6 chance of being the same as the first. Hence the probability of getting two numbers the same is 1/6.
What is the probability of rolling a 6 the first time and a 1 the second time
Both are equivalent! * Probability of using 50-50 and getting the right answer: 1/2 * Probability of using double dip and getting the right answer: = Probability that either first or the second guess is correct P(First guess is correct) = 1/4 + P(First guess in wrong and second guess is correct) = 3/4 * 1/3 = 1/4 = 1/2
Assuming it is a standard poker deck with 52 cards and 4 aces The probability of getting your first card an ace is = 4/52 Over here you need to reread your questions. There are something you need to know before i continue - when you draw your second card, did you return the first card back into the pile? lets say if you draw an ace of spades, would you be able to redraw it again for the second card? If the first ace is return to the pile: probability of getting a second ace is also 4/52 so the total probability of getting both cards an ace is (4/52 x 4/52) If the first ace is not return to the pile: probability of getting a second ace is now 3/51 note that removing one ace also removes one card from the pile. total card is now 51 with 3 aces only so the total probability of getting both cards an ace is (4/52 x 3/51) hope i help.
2/12 or 1/6
The probability that the second coin matches the first is 0.5 .The probability that the third coin matches the first is 0.5 .The probability that the second and third coins both match the first is (0.5 x 0.5) = 0.25 = 25%
The probability of drawing the first ace is 4 in 52. The probability of getting the second ace is 3 in 51. The probability of getting the third ace is 2 in 50. The probability, then, of drawing three aces is (4 in 52) times (3 in 51) times (2 in 50), which is 24 in 132600, or 1 in 5525, or about 0.0001810