There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.
However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of 3 girls out of 4 children is 0.2331
50%
Assuming that the probability of having a baby girl is 1/2 and that of having a baby boy is 1/2, the probability of having 3 baby girls in a row is (1/2)(1/2)(1/2)=1/8.
1/8
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, the probability of three out of three being girls is 0.1127.
4/6=2/4 n(s)=3 6
50%
3 out of 7
The chances of a couple having 2 girls and 1 boy among 3 children can be calculated using the probability of each combination. Assuming each child is equally likely to be a boy or a girl, the probability of having 2 girls and 1 boy is given by the binomial probability formula. There are three possible arrangements for 2 girls and 1 boy (GGB, GBG, BGG), making the probability approximately 3 out of 8, or 37.5%.
It is 3/8.
Assuming that the probability of having a baby girl is 1/2 and that of having a baby boy is 1/2, the probability of having 3 baby girls in a row is (1/2)(1/2)(1/2)=1/8.
The probability of exactly 3 girls in a family of 10 children, assuming equal chance of a boy or girl, is 0.1172. This is a binomial distribution.
1/8
The probability is1 - [Prob(No children) + Prob(1 child, a girl) + Prob(2 children, both girls) + Prob(3 children, all girls) + ...]Not all relevant information is readily available.
1/32
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, the probability of three out of three being girls is 0.1127.
To determine the probability of selecting a family with exactly 3 male children out of 4, we can use the binomial probability formula. The probability of having a male child is typically considered to be 0.5 (assuming an equal likelihood of male and female). The probability of exactly 3 males in 4 children is calculated as ( P(X = 3) = \binom{4}{3} (0.5)^3 (0.5)^1 = 4 \times 0.125 \times 0.5 = 0.25 ). Thus, the probability is 0.25 or 25%.
Assuming that children of either gender are equally likely, the answer is (1/2)3 = 1/8