For each birth, you have two choices - either a boy or a girl. Then, the probability for a certain birth to obtain a choice is ½.
Using Binomial Theorem, we have (10 choose 8)(½)8(½)² = 45/1024.
0.48
This is a Binomial Probability; p=0.5, n=10 & x=7. Since you want the probability of exactly 7, in the related link calculator, after placing in the above values, P(x=7) = 0.1172 or 11.72%.
The probability of having a boy or a girl in any single birth is generally considered to be approximately equal, around 50% for each gender. Therefore, even if a couple has 5 boys, the probability of their next child being a boy remains 50%. Past births do not influence the outcome of future births due to the independence of each event.
The probability of having 2 boys and 1 girl in a family with three children can be calculated using the binomial probability formula. Assuming the probability of having a boy or a girl is equal (1/2 each), the probability of having 2 boys and 1 girl can be found by considering the different combinations (BBG, BGB, GBB). Therefore, the probability is ( \frac{3}{8} ) or 37.5%.
6 out of 9.
25
0.48
This is a Binomial Probability; p=0.5, n=10 & x=7. Since you want the probability of exactly 7, in the related link calculator, after placing in the above values, P(x=7) = 0.1172 or 11.72%.
In a family with four children, the probability of having four boys is 1 in 16.
6 out of 9.
1/8
50/50
3/8
These events are independent; so the probability of a girl is 0.5.
Assuming that having boys and girls are equally likely, then the probability is 1/8. * * * * * You also need to assume that the children's genders are independent. They are NOT and depend on the parents' ages and genes.
1/4
Since the probability of having a son is about 1/2, the probability of the first 4 children being boys is about (1/2)4.