It is 1/2 (1/4 SS + 1/4 Ss)
From the cross Aa x Aa, the probability of producing a homozygous dominant offspring is 1/4 or (0.25).
well, it depends on the genes of the parents
Impossible. You can only be heterozygous or homozygous, not both.
It is 1/2 (1/4 SS + 1/4 Ss)
Here are the four possibilities: AA Aa Aa aa Therefore there is a 25% chance of producing a homozygous dominant offspring (AA).
From the cross Aa x Aa, the probability of producing a homozygous dominant offspring is 1/4 or (0.25).
well, it depends on the genes of the parents
Impossible. You can only be heterozygous or homozygous, not both.
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
25%
The probability of offspring for two heterozygous dogs (Aa x Aa) is 25% homozygous dominant (AA), 50% heterozygous (Aa), and 25% homozygous recessive (aa) based on Mendelian genetics principles.
It is 1/2 (1/4 SS + 1/4 Ss)
1/16
Here are the four possibilities: AA Aa Aa aa Therefore there is a 25% chance of producing a homozygous dominant offspring (AA).
If a homozygous black guinea pig (BB) is crossed with a homozygous white guinea pig (bb), all offspring will inherit one black allele (B) from the black parent and one white allele (b) from the white parent, resulting in heterozygous offspring (Bb). Since black fur is dominant over white fur, all offspring will have black fur. Therefore, the probability of an offspring having black fur is 100%.
If one parent is homozygous dominant (AA) and the other parent is homozygous recessive (aa), all offspring will inherit one dominant allele and display the dominant phenotype. Therefore, the probability of their offspring exhibiting the dominant phenotype is 100%.
Given those conditions, the offspring have a 50% chance of demonstrating the dominant phenotype and a 50% chance of demonstrating the recessive phenotype.