From the cross Aa x Aa, the probability of producing a homozygous dominant offspring is 1/4 or (0.25).
well, it depends on the genes of the parents
Impossible. You can only be heterozygous or homozygous, not both.
It is 1/2 (1/4 SS + 1/4 Ss)
Here are the four possibilities: AA Aa Aa aa Therefore there is a 25% chance of producing a homozygous dominant offspring (AA).
From the cross Aa x Aa, the probability of producing a homozygous dominant offspring is 1/4 or (0.25).
well, it depends on the genes of the parents
Impossible. You can only be heterozygous or homozygous, not both.
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
25%
The probability of offspring for two heterozygous dogs (Aa x Aa) is 25% homozygous dominant (AA), 50% heterozygous (Aa), and 25% homozygous recessive (aa) based on Mendelian genetics principles.
1/16
It is 1/2 (1/4 SS + 1/4 Ss)
Here are the four possibilities: AA Aa Aa aa Therefore there is a 25% chance of producing a homozygous dominant offspring (AA).
If one parent is homozygous dominant (AA) and the other parent is homozygous recessive (aa), all offspring will inherit one dominant allele and display the dominant phenotype. Therefore, the probability of their offspring exhibiting the dominant phenotype is 100%.
Given those conditions, the offspring have a 50% chance of demonstrating the dominant phenotype and a 50% chance of demonstrating the recessive phenotype.
If the individual heterozygous for a cleft chin mates with an individual homozygous for chin without a cleft, their offspring can inherit their recessive allele for chin without a cleft. This would make their offspring homozygous recessive for chin without a cleft. The probability of this occurring is 50%.