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well, it depends on the genes of the parents

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What is the probability of a homozygousrecessive offspring explain?

The probability of a homozygous recessive offspring depends on the genotypes of the parents. If we consider a simple Mendelian trait with two alleles (dominant "A" and recessive "a"), a homozygous recessive offspring (aa) will occur if both parents contribute a recessive allele. For instance, if both parents are heterozygous (Aa), the probability of producing a homozygous recessive offspring is 25%, as determined by a Punnett square. If one parent is homozygous dominant (AA) and the other is homozygous recessive (aa), the probability of a homozygous recessive offspring is 0%.


What is the probability that offspring of a cross between a homozygous recessive parent and a hetezyguous parent will be homozygous recessive?

In a cross between a homozygous recessive parent (AA) and a heterozygous parent (Aa), the possible genotypes of the offspring are 50% homozygous recessive (AA) and 50% heterozygous (Aa). Therefore, the probability that an offspring will be homozygous recessive is 50%.


What is the probability that the offspring of a homozygous dominant individual and a homozygous recessive individual exhibit the dominant phenotype?

Given those conditions, the offspring have a 50% chance of demonstrating the dominant phenotype and a 50% chance of demonstrating the recessive phenotype.


What fraction of the offspring resulting from a heterozygous by heterozygous dihybrid cross are homozygous recessive for both traits?

In a dihybrid cross between two heterozygous parents (AaBb x AaBb), the probability of producing homozygous recessive offspring for both traits (aabb) is 1/16. This is derived from the Punnett square, where the combinations of alleles reveal that out of 16 possible offspring, only one combination results in homozygous recessive for both traits. Thus, the fraction of homozygous recessive offspring is 1/16.


What is the probability that the offspring of a homozygous dominant parent and a heterozygous parent will show a recessive phenotype?

The probability that the offspring of a homozygous dominant parent (AA) and a heterozygous parent (Aa) will show a recessive phenotype is 0%. Since the homozygous dominant parent contributes only dominant alleles (A), all offspring will inherit at least one dominant allele (A) from the homozygous parent, resulting in either a homozygous dominant (AA) or a heterozygous (Aa) genotype, both of which express the dominant phenotype.

Related Questions

What is the probability of a homozygousrecessive offspring explain?

The probability of a homozygous recessive offspring depends on the genotypes of the parents. If we consider a simple Mendelian trait with two alleles (dominant "A" and recessive "a"), a homozygous recessive offspring (aa) will occur if both parents contribute a recessive allele. For instance, if both parents are heterozygous (Aa), the probability of producing a homozygous recessive offspring is 25%, as determined by a Punnett square. If one parent is homozygous dominant (AA) and the other is homozygous recessive (aa), the probability of a homozygous recessive offspring is 0%.


What is the probability that offspring of a cross between a homozygous recessive parent and a hetezyguous parent will be homozygous recessive?

In a cross between a homozygous recessive parent (AA) and a heterozygous parent (Aa), the possible genotypes of the offspring are 50% homozygous recessive (AA) and 50% heterozygous (Aa). Therefore, the probability that an offspring will be homozygous recessive is 50%.


What is the probability of 2 heterozygous individuals producing a heterozygous recessive offspring?

The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.


What is the probability of 2 heterozygous individuals producing a homozygous recessive offspring?

25%


What is the probability of offspring for 2 heterozygous dogs?

There are 3 probabilities: dominant homozygous, recessive homozygous, or heterozygous.


In crossing a homozygous recessive with a heterozygote what is the chance of getting a homozygous recessive phenotype in the F1 generation?

1/2 or 50%. The homozygous recessive gentoype contains two recessive alleles for the gene for a trait. So the homozygous recessive individual can pass on only recessive alleles to an offspring. The heterozygous individual has one dominant and one recessive allele for the gene for a trait. So the heterozygous individual can pass on either a dominant or a recessive allele to an offspring. So if an offspring inherits a recessive allele from the heterozygous parent, along with the recessive allele from the homozygous recessive parent, it will have the homozygous recessive genotype and phenotype.


What is the probability that the offspring of a homozygous dominant individual and a homozygous recessive individual exhibit the dominant phenotype?

Given those conditions, the offspring have a 50% chance of demonstrating the dominant phenotype and a 50% chance of demonstrating the recessive phenotype.


What is the probability that an individual heterozygous for a cleft chin and individual homozygous for chin without cleft will produce offsprings that are homozygous recessive for chin without cleft?

The probability that an individual heterozygous for a cleft chin and an individual homozygous for a chin without a cleft will produce offspring that are homozygous recessive for a chin without a cleft is fifty percent. You can calculate this by making a Punnet square.


The probability of a homozygous recessive offspring resulting from a cross between two homozygous dominant individual is?

It depends on the parents. The parent could have two dominant genes which would give a 0% chance of the offspring being recessive. The only way that the offspring could have a recessive characteristic is if the both parents have one dominant and one recessive gene, a 25% chance. The chance that both parents would pass on the recessive gene (if they have one dominant and recessive gene) is also 25%, because there is a 50% chance for each parent.


If a test cross between a homozygous recessive and heterozygous allele will yield what percent of offspring as homozygous recessive?

A test cross between a homozygous recessive and a heterozygous individual will yield 50% of offspring as homozygous recessive. This is because all the offspring will inherit one recessive allele from the homozygous recessive parent.


How do two heterozygous organisms produce on offspring with a recessive phenotype?

There are two forms of Homozygous inheritance: Homozygous Dominant, and Homozygous Recessive. In order for two parents that are Homozygous to produce a Heterozygous offspring, one of them MUST be Homozygous Dominant, and the other MUST be Homozygous Recessive.


What is the probabilty that the offspring of a homozygous domiant idiviual and a homozygous recessive indiviual will exbhit the domaint phenotype?

If one parent is homozygous dominant (AA) and the other parent is homozygous recessive (aa), all offspring will inherit one dominant allele and display the dominant phenotype. Therefore, the probability of their offspring exhibiting the dominant phenotype is 100%.