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A box contains 8 green marbles 4 red marbles and 4 purple marbles if you draw a marble at random what is the probability that you will not draw a red marble?
Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4
A bag contains 8 marbles 4 are blue 3 are green and one is orange you draw out one marble and then another without replacing the first marble Find the probability of drawing 2 blue marbles?
Probability of drawing a blue marble first is 4 in 8 (or 50%) Probability of drawing a blue marble second is 3 in 7 (or 42.85714%) Probablility of drawing blue then blue is the two above multiplied 0.5 * 0.4285714 Which is 0.212142407 or 21% or One in Five.
A bag has 13 green marbles What is the probability pf drawing out a green marble?
your probability would be 13/13. you would have a 100 percent chance of getting a green marble
A bag contains 6 red marbles 7 blue marbles and 6 green marbles If one marble is randomly picked from the bag what is the probability that this is a blue marble?
There would be a 7/19 or 36.84% chance of drawing a blue marble from the bag.
In a standard deck of 52 playing cards what is the probability of not drawing an ace on one draw?
Probability of not drawing an ace equals one minus the probability of drawing an ace. The probability of drawing an ace is 4/52 or 1/13. So the probability of not drawing an ace on one draw is 1 - 1/13 or 12/13 or 0.9231 (92.31%).
