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A box contains 8 green marbles 4 red marbles and 4 purple marbles if you draw a marble at random what is the probability that you will not draw a red marble?
Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4
A bag contains 8 marbles 4 are blue 3 are green and one is orange you draw out one marble and then another without replacing the first marble Find the probability of drawing 2 blue marbles?
Probability of drawing a blue marble first is 4 in 8 (or 50%) Probability of drawing a blue marble second is 3 in 7 (or 42.85714%) Probablility of drawing blue then blue is the two above multiplied 0.5 * 0.4285714 Which is 0.212142407 or 21% or One in Five.
A bag has 13 green marbles What is the probability pf drawing out a green marble?
your probability would be 13/13. you would have a 100 percent chance of getting a green marble
What is the probability of not drawing a green marble?
To calculate the probability of not drawing a green marble, first determine the total number of marbles and the number of green marbles. The probability of not drawing a green marble is then given by the ratio of the number of non-green marbles to the total number of marbles. This can be expressed as: [ P(\text{not green}) = \frac{\text{Number of non-green marbles}}{\text{Total number of marbles}}. ] Without specific numbers, the exact probability cannot be computed.
A bag contains 6 red marbles 7 blue marbles and 6 green marbles If one marble is randomly picked from the bag what is the probability that this is a blue marble?
There would be a 7/19 or 36.84% chance of drawing a blue marble from the bag.
A bag contains 3 blue marbles 7 red marbles and 5 yellow marbles. If Joe picks 1 marble from the bag at random what is the probability that it will be blue?
A bag of marbles contains 13 marbles. 5 Blue, 3 Yellow, 4 Green and 1 Red. Leave all answers as a ratio in lowest terms. 18 points On a single draw, what is the probability of drawing a yellow marble? What is the probability of not drawing a yellow marble? What are the odds in favor of drawing a blue marble? What is the probability of drawing a red or yellow marble? What is the probability of drawing a purple marble? If you had to bet on drawing a marble of a certain color what color would you not choose?
A box contains 8 green marbles 4 red marbles and 4 purple marbles if you draw a marble at random what is the probability that you will not draw a red marble?
Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4
There are 9 red and 6 blue marbles in a jar If you draw red marbles from the jar 7 times what is the experimental probability of drawing a red marble?
The answer is dependent on whether of not you replace the marbles in the jar. If you do, the probability of drawing a red marble is 9 in 15 or 60%, every time. If you do not replace the marbles, the probability of drawing a red marble is 2 in 8 or 25%.
What is the probability of drawing a marble that is not white?
It depends on how many marbles of each colour you have....
A bag contains 8 marbles 4 are blue 3 are green and one is orange you draw out one marble and then another without replacing the first marble Find the probability of drawing 2 blue marbles?
Probability of drawing a blue marble first is 4 in 8 (or 50%) Probability of drawing a blue marble second is 3 in 7 (or 42.85714%) Probablility of drawing blue then blue is the two above multiplied 0.5 * 0.4285714 Which is 0.212142407 or 21% or One in Five.
A bag has 13 green marbles What is the probability pf drawing out a green marble?
your probability would be 13/13. you would have a 100 percent chance of getting a green marble
What is the probability of not drawing a green marble?
To calculate the probability of not drawing a green marble, first determine the total number of marbles and the number of green marbles. The probability of not drawing a green marble is then given by the ratio of the number of non-green marbles to the total number of marbles. This can be expressed as: [ P(\text{not green}) = \frac{\text{Number of non-green marbles}}{\text{Total number of marbles}}. ] Without specific numbers, the exact probability cannot be computed.
If a box contains 4 red marbles seven white and 5 blue and two marbles are drawn one at a time with replacement What is the probability that both marbles are white?
Since the box contains 16 marbles, seven of them white, then the probability of drawing one white marble is 7/16. If you replace the marble and draw again, the probability of drawing another white marble is still 7/16. The net probability of drawing two white marbles, while replacing the first, is 49/256.
12 red marbles and 15 marbles are blue. if one marble is drawn from the bag What is the probabilitythe marble is not be red?
15/27. Simply take the probability of drawing a blue marble.
If you have a bag containing 24 marbles If the probability of drawing a red marble is twice as likely not drawing a red marble how many red marbles are in the bag?
Suppose probability of drawing a red marble is p. Then p = 2*(1 - p) that is p = 2 - 2p or p = 2/3 So 2/3 of the 24 marbles are red 24*(2/3) = 16 red marbles.
What is the probability of drawing a white marble then a red marble if there are 3 red marbles and 2 white marbles?
5 marbles. 3 red marbles, 2 white marbles.The probability of drawing a white marble is P(W) = 2/5 = 0.40If the white marble is not returned to the rest of the marbles (no substitution), theprobability that the second marble drawn is a red one is P(R) = 3/4 = 0.75.The probability that the event of drawing first a white marble and without substitutionthe second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/4) = 6/20 = 3/10 = 0.30 = 30.0%.If the process of drawing the marbles is with substitution, the probability of thesecond draw turning a red marble is P(R) = 3/5 = 0.60 = 60.0%The probability that the event of first drawing a white marble and after returning themarble back to the original group of marbles (with substitution) the second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/5) = 6/25 = 0.24 = 24.0%.
A bag contains 2 yellow 12 red and 6 green marbles What is the probability of selecting a red marble replacing it then selecting another red marble?
The probability of drawing two reds, with replacement, is the same as the probability of drawing a red, times itself. So: P(drawing two reds) = P(drawing a red)2 = (12/(2 + 12 + 6))2 = (12/20)2 = (3/5)2 = 9/25
