To determine the probability of obtaining 45 or fewer heads in 100 tosses of a fair coin, you can use the binomial distribution model. The number of trials (n) is 100, and the probability of success (getting heads) on each trial (p) is 0.5. The cumulative probability can be calculated using statistical software or a binomial probability table, yielding a result near 0.5, as 45 heads is close to the mean of 50 heads expected in 100 tosses. For precise calculations, employing the normal approximation to the binomial distribution can also provide an estimate.
It is 93/256 = 0.363 approx.
The probability is 0, since there will be some 3-tosses in which you get 0, 1 or 3 heads. So not all 3-tosses will give 2 heads.
The probability that a coin will land on heads - at least once - in six tosses is 0.9844
The probability is 1 out of 5
The probability is 0.09766%.Each toss has a ½ chance to be heads. To combine probabilities use multiply them. So the probability to get two heads out of two tosses is ½ * ½, and three heads out of three tosses is ½ * ½ * ½. So the exact answer is 0.5^10
It is 93/256 = 0.363 approx.
The probability is 0, since there will be some 3-tosses in which you get 0, 1 or 3 heads. So not all 3-tosses will give 2 heads.
The probability of tossing heads on all of the first six tosses of a fair coin is 0.56, or 0.015625. The probability of tossing heads on at least one of the first six tosses of a fair coin is 1 - 0.56, or 0.984375.
The probability that a coin will land on heads - at least once - in six tosses is 0.9844
The probability is 1 out of 5
The probability is 0.09766%.Each toss has a ½ chance to be heads. To combine probabilities use multiply them. So the probability to get two heads out of two tosses is ½ * ½, and three heads out of three tosses is ½ * ½ * ½. So the exact answer is 0.5^10
Theoretical probability = 0.5 Experimental probability = 20% more = 0.6 In 50 tosses, that would imply 30 heads.
1/4
The conditional probability is 1/4.
It is 3/8.
It is 0.5
2 out of 3 i think