The answer depends on how many dice you are rolling and how many times.
The probability is 21/36 = 7/12
It is 15/36.
The probability of rolling a 7 on a pair of 2 dices is: P(7) = 6/36.The probability of rolling a 11 on a pair of 2 dices is: P(11) = 2/36.The probability of rolling 7 or 11 is the sum of both single probabilities:P(7 or 11) = 6/36 + 2/36 = 8/36 = 2/9 = 0.2222... ≈ 22.2%.Explanation.When rolling a pair of fair dice there are 36 possible equiprobable events oroutcomes. They are:(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),(3,1), . . . . . . . . . . . . . . . . . , (3,6),(4,1), . . . . . . . . . . . . . . . . . , (4,6),(5,1), . . . . . . . . . . . . . . . . . , (5,6),(6,1), . . . . . . . . . . . . . . . . . , (6,6).Each of these 36 events has the probability of happening of 1/36.For the case of the sum of both dice to be 7, there are 6 possible outcomes, so theprobability of the event sum equals 7 is: P(7) = 6/36 = 1/6.For the case of the sum of both dice to be 11, there are 2 possible outcomes, (6,5)and (5,6), so the probability of the event sum equals 11 is: P(11) = 2/36 = 1/18.
Probability that the sum is 6 = 5/36 Probability that the sum is 7 = 6/36
The probability is 1/6.
The answer depends on how many dice you are rolling and how many times.
The probability of rolling a sum of 11 with 2 dice is: P(11) = 1/18.For explanation see answer to question: "What is the probability of rolling 7 or 11 with 2 dice?".Read more: What_is_the_probability_of_rolling_7_or_11_with_2_dice
The probability is 21/36 = 7/12
Te probability of rolling a sum of 7 with two fair dice is 6 in 36, or 1 in 6, or about 0.1667.Of all the possible combinations of two dice, the sum of 7 has the highest probability, with the other combinations decreasing down to 2 and 12, with probabilities of 1 in 36, or about 0.0278.
There are 216 permutations of three dice. Of these, 15 sum to 7. Therefore, the probability of rolling a sum of 7 with three dice is 15 in 216, or 5 in 72, or about 0.06944.111112113114115711612112212312471251261311321337134135136141142714314414514615171521531541551561611621631641651662112122132147215216221222223722422522623123272332342352362417242243244245246251252253254255256261262263264265266311312313731431531632132273233243253263317332333334335336341342343344345346351352353354355356361362363364365366411412741341441541642174224234244254264314324334344354364414424434444454464514524534544554564614624634644654665117512513514515516521522523524525526531532533534535536541542543544545546551552553554555556561562563564565566611612613614615616621622623624625626631632633634635636641642643644645646651652653654655656661662663664665666
It is 15/36.
Possible outcomes for one cube = 6 .Possible outcomes for 2 cubes = 6 x 6 = 36 .Ways to roll a sum of 7 = 6 ways,1, 6 . . . 2, 5 . . . 3, 46, 1 . . . 5, 2 . . . 4, 3Probability of rolling a 7 on the first roll = 6/36 = 1/6 .Probability of rolling a 7 on the second roll = 6/36 = 1/6 .Probability of rolling a 7 on the third roll = 6/36 = 1/6 .Probability of rolling a sum of 7 three times in a row = (1/6 x 1/6 x 1/6) = (1/6)3 = 1/216 = 0.00463 = 0.463%Probability of not rolling a sum of 7 three times in a row = 1 - (probability of doing it) = 99.537%
There are 36 permutations of rolling two standard dice. Of them, four (1+4, 2+3, 3+2, and 4+1) sum to five, and three (6+4, 5+5, and 4+6) sum to ten. The probability, then of rolling a multiple of five is 7 in 36, or about 0.1944.
The probability of rolling a 7 with 2 dice is 6/36; probability of rolling an 11 is 2/36. Add the two together to find probability of rolling a 7 or 11 which is 8/36 or 2/9.
-- There are (6 x 6) = 36 possible rolls for a fair pair of 6-sided dice.-- There are 6 ways to roll a sum of 7 :1 ... 62 ... 53 ... 44 ... 35 ... 26 ... 1-- So the probability is 6/36 = 1/6 = 162/3 % .-- The probability is the probability, not the 'theoretical' probability.
The probability of rolling a 7 on a standard die is 0. It will not ever happen.