To determine the probability of spinning a multiple of 3, you first need to know the range of numbers on the spinner. For example, if the spinner has numbers from 1 to 12, the multiples of 3 are 3, 6, 9, and 12, totaling 4 favorable outcomes. The probability is then calculated as the number of favorable outcomes divided by the total number of outcomes. In this case, the probability would be 4/12, which simplifies to 1/3.
The probability of spinning the number 3, or any number, is 1/4 or 0.25 since there is 4 numbers total.
Assuming that the four-sided spinner is fair and that it is numbered in the traditional way of 1, 2, 3 and 4, the probability of spinning a three is 1/4.
It is 1/3.It is 1/3.It is 1/3.It is 1/3.
To find the probability of spinning a number greater than 5 on a spinner numbered 1 to 8, we note that the numbers greater than 5 are 6, 7, and 8, giving us 3 favorable outcomes out of 8 total outcomes. Thus, the probability of this event is 3/8. For the coin toss, the probability of getting a tail is 1/2. The combined probability of both events occurring is (3/8) × (1/2) = 3/16.
The probability is 35/36.
To calculate the probability of spinning a multiple of 3 on a spinner labeled 1 through 10, we first determine the total number of favorable outcomes. The multiples of 3 between 1 and 10 are 3, 6, and 9. Therefore, there are 3 favorable outcomes. Since there are a total of 10 equally likely outcomes on the spinner, the probability of spinning a multiple of 3 is 3/10 or 0.3.
The probability of spinning the number 3, or any number, is 1/4 or 0.25 since there is 4 numbers total.
Assuming that the four-sided spinner is fair and that it is numbered in the traditional way of 1, 2, 3 and 4, the probability of spinning a three is 1/4.
The probability is 3/7.
The probability that you roll a multiple of 3 (3 and 6) in a fair die is: P(3 or 6) = 2/6=1/3 = 0.333... ≈ 33.3%.The probability that you roll a multiple of 5 (5) is: P(5) = 1/6.The probability that you roll a multiple of 3 or 5 is: P(3 or 6 or 5) = 2/6 + 1/6 = 1/2 = 0.50 = 50%
In general, you cannot. The answer depends on the shape of the spinner - how many sides it has and what numbers are on it.
It is 1/3.It is 1/3.It is 1/3.It is 1/3.
To find the probability of spinning a number greater than 5 on a spinner numbered 1 to 8, we note that the numbers greater than 5 are 6, 7, and 8, giving us 3 favorable outcomes out of 8 total outcomes. Thus, the probability of this event is 3/8. For the coin toss, the probability of getting a tail is 1/2. The combined probability of both events occurring is (3/8) × (1/2) = 3/16.
The probability is 35/36.
The probability of spinning the spinner and landing on an odd number depends on the number of odd numbers on the spinner and the total number of numbers on the spinner. If there are 3 odd numbers on the spinner and a total of 6 numbers, then the probability of landing on an odd number is 3/6, which simplifies to 1/2 or 50%.
The answer depends on the domain. If the selection is made from any real or rational numbers, the probability is 0. If the domain is all integers (or all positive integers) then the probability is 1/3. If it is some other subset of integers, then the answer is a rational number between 0 and 1/3.
what game are you referring to?