The probability of spinning the spinner and landing on an odd number depends on the number of odd numbers on the spinner and the total number of numbers on the spinner. If there are 3 odd numbers on the spinner and a total of 6 numbers, then the probability of landing on an odd number is 3/6, which simplifies to 1/2 or 50%.
The depends on what other numbers exist on the spinner. If there are a total of six numbers on the spinner, for instance, the probability of spinning a 1-4 is 2 in 3.
its the number of odd numbers (3) divided by the total number of numbers (6) 3/6 = 0.5
3/16
Well, numbers divisible by 2 are even numbers, and the even numbers from 1 to 6 are 2,4,and 6. Since there are 3 out of 6 even numbers on a number cube, there is a probability 1/2 to roll an even number on a number cube.
The probability of spinning the spinner and landing on an odd number depends on the number of odd numbers on the spinner and the total number of numbers on the spinner. If there are 3 odd numbers on the spinner and a total of 6 numbers, then the probability of landing on an odd number is 3/6, which simplifies to 1/2 or 50%.
In general, you cannot. The answer depends on the shape of the spinner - how many sides it has and what numbers are on it.
The depends on what other numbers exist on the spinner. If there are a total of six numbers on the spinner, for instance, the probability of spinning a 1-4 is 2 in 3.
The probability is 3/7.
The probability is 3 out of 10.
Assuming each possible number on a spinner has the same probability and an unbiased die is being rolled, the answer depends on how many numbers are on the spinner, and how many times the number 4 appears on each.To find the probability, workout the probability of spinning a 4 on the spinner and the probability of rolling a 4 on the die; then as spinning the spinner has no effect on rolling the die, they are independent events and to get the probability of both happening multiply them together.The probability of success is the number of successful outcomes divided by the total number of outcomes, giving:Probability(spinning a 4) = how_many_4s_are_on_the_spinner / how_many_numbers_are_on_the_spinnerProbability(rolling a 4) = how_many_4s_are_on_the_die / how_many_numbers_are_on_the_dieProbability(spinning a 4 and rolling a 4) = Probability(spinning a 4) × Probability(rolling a 4)Examples:an octagonal spinner with the numbers 1-4 on it each twice and a tetrahedral die (as used in D&D games) with the numbers 1-4 on it→ pr(spin 4 & roll 4) = 2/8 × 1/4 = 1/16a decagonal spinner with the numbers 0-9 and a tetrahedral die with the numbers 0-3 on it→ pr(spin 4 & roll 4) = 1/10 × 0/4 = 0a decagonal spinner with the numbers 0-9 and a standard die with the numbers 1-6 on it→ pr(spin 4 & roll 4) = 1/10 × 1/6 =1/60
If each of the numbers on the spinner is equally likely, then the answer is 0.3
It depends on the number of numbers on the spinner and what those numbers are.
8 numbers in total, 4 of those numbers are odd (1, 7, 5 and 3) so 4/8 = 1/2 aka 50%, 0.5
If it is a fair spinner, then 3/8
The prime numbers from one to nine are 2, 3, 5, and 7. There are nine numbers from one to nine. The probability is 4 (the number of prime numbers) over 9 (the total number of numbers). Therefore, the probability of choosing a prime number is 4/9 or about 44 percent.
its the number of odd numbers (3) divided by the total number of numbers (6) 3/6 = 0.5