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Q: What is the probability of the 3 cubes that the product is prime?

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3/5 or three fifths.

The prime factors of 36 are 2, 2, 3, and 3, so their product is 36. The distinct prime factors of 36 are 2 and 3, so their product is 6.

The product of its prime factors are: 3*3*3*3 = 81

2 and 3 are the smallest prime numbers. So answer is 2^3 * 3^3 = 216

As a product of its prime factors: 2*2*3*3 = 36 or as 22*32 = 36 As a product of its prime factors: 3*13 = 39

Related questions

7/10

The prime factors of 99 are 3 and 11. Their cubes are 27 and 1331.

If the number cubes are standard dice cubes, the odds of rolling 3 ones is 1 in 216.

"The probability of getting a prime number in a die is 4/6" Actually there are 3 prime numbers on a die. 2, 3, and 5 are all prime numbers. So this tells you that you have 3 chances it will be a prime number and 3 chances it will not be a prime number. So the probability of getting a prime number on a die would be 3/6 or 1/2.

With a single cube, the probability is 100%With two cubes, the probability is 15/36 = 5/12 = 412/3 %

The probability is 3 out of 10.

As a product of its prime factors: 3*3*3*11 = 297

As a product of its prime factors: 3*3*11 = 99

As a product of its prime factors: 3*3*7 = 63

As a product of its prime factors: 2*2*3*3 = 36

3 is a prime number.

The prime factors of 18 are 2, 3, and 3. The product of these prime factors is 18.The distinct prime factors of 18 are 2 and 3. The product of these distinct prime factors is 6.

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