If only one person is a carrier of cystic fibrosis than there is no chance of having a child with it. Both parents have to be carriers and even then there is only a 25% chance. If only one carries than there is a 50% chance that their children will carry but will not have cystic fibrosis.
Zero. Cystic fibrosis is an autosomal recessive disease. This means that both parents must carry a mutated gene and have a 1 in 4 (25%) chance of having a child with CF.
Genotype is used to determine the probability of having specific offspring from two known parents.
It would depend on the parents' genes and age. Globally, the probability is approx 0.483
well, it depends on the genes of the parents
3:4 or 75%
The probability of a child having cystic fibrosis in this scenario is 50%. If one parent is homozygous dominant (no cystic fibrosis allele) and the other is a carrier (heterozygous), there is a 50% chance of passing on the cystic fibrosis allele to their child, resulting in the child having cystic fibrosis.
To have cystic fibrosis both parents have to be a carrier. Each parent passes on one of their genes to their children; they each have one healthy and one cystic fibrosis gene. The child with cystic fibrosis receives a cystic fibrosis gene from each parent. The other child has at least one healthy gene if she does not have cystic fibrosis, though she could be a carrier. hope it would help
A Punnett square for cystic fibrosis would involve crossing two parents who are carriers of the recessive allele for the disease (denoted as "cf"). The square would show the probability of having a child with cystic fibrosis (25%), a carrier (50%), or unaffected by the disease (25%). Each parent would have a genotype of "Cf" (carrier) for the Punnett square.
Yes, since the disease is a recessive inherted trait BOTH parents must carry the gene but will not have the disease itself. Approximately 30,000 people in the United States have cystic fibrosis. An additional ten million more-or about one in every 31 Americans-are carriers of the defective CF gene, but do not have the disease. The disease is most common in Caucasians, but it can affect all races.
you need two parents to get it but one parent to become a carrier. You need two parents with one of the alleles to inherit it but if you have one parent with the allele you might be a carrier. If you have two parents with the allele it does not mean that you will definitely have it. This is because the allele for cystic fibrosis is recessive.
If both parents are carriers of the cystic fibrosis gene, each child has a 25% chance of inheriting two copies of the gene and having cystic fibrosis, a 50% chance of being a carrier like the parents, and a 25% chance of not inheriting any copies of the gene. Therefore, the percentage of a child not having cystic fibrosis with carrier parents is 25%.
Let's call the gene "C." Capital C means no cystic fibrosis; lower c means cystic fibrosis, since it is a recessive gene. CC is a person who does not have cystic fibrosis and also is not a carrier. Cc indicated a carrier. cc shows a person with cystic fibrosis. In order for a child to have cystic fibrosis, its parents must be: 1. cc and cc (both have cystic fibrosis, so every child will as well.) 2. Cc and Cc (both carriers; 25% chance of having a child with cystic fibrosis) 3. Cc and cc (one parent is a carrier and one has cystic fibrosis; there is a 50% chance that the children will have cystic fibrosis.)
Zero. Cystic fibrosis is an autosomal recessive disease. This means that both parents must carry a mutated gene and have a 1 in 4 (25%) chance of having a child with CF.
To have a child with cystic fibrosis both parents must be a carrier or a sufferer. A carrier is a person who has one healthy gene, and one diseased gene, so they dont have cystic fibrosis but they can pass it on to their children. Children inherit one gene from each parent. To get cystic fibrosis a child must get two copies of the 'disease' gene - one from each parent. If two carriers have children, each child has a 25% chance not getting a Cystic fibrosis disease gene, 50% of being a carrier and 25% of being a sufferer. This is not affected by if the child is male or female. So essentially the answer is bad luck.
If both parents are carriers then the child has a 25% chance of having cystic fibrosis. If one parent has CF and the other the other was just a carrier then the child has a 50% chance of having CF. If one parent has CF and the other has two normal genes then there is no chance of the child having CF. If one parent is a carrier and the other has two normal genes then there is no chance of the child having CF. If both parents have CF then there is a 100% chance that the child will also have CF.
A child can have cystic fibrosis if both parents carry a copy of the mutated gene responsible for the condition. In this case, the parents are carriers of the cystic fibrosis gene but do not have the disease themselves. When both parents pass the carrier gene to their child, the child can inherit two copies of the mutated gene and develop cystic fibrosis.
In order to have a child with cystic fibrosis, both parents must be carriers (assuming neither of the parents actually have CF; then obviously they will have symptoms). In CF, a carrier has no symptoms, unlike sickle cell anemia, where a carrier will have mild symptoms of the disease. A carrier of CF has only one defected 7th chromosome, and the other unaffected one makes the CFTR gene work correctly. When both are defected, the result is the CF disease, and normal CFTR genes are impossible to make, causing the person to have the disease.