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What are the chances of a normal person and a carrier for cystic fibrosis have a kid with cystic fibrosis?
Wiki User
∙ 12y ago
Zero. Cystic fibrosis is an autosomal recessive disease. This means that both parents must carry a mutated gene and have a 1 in 4 (25%) chance of having a child with CF.
Wiki User
∙ 12y ago
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A male who has normal vision marries a female who is a carrier for colorblindness can they have a colorblind daughter?
Assuming that the man who has normal vision is homozygous for normal vision, the couple's daughter will either be homozygous for normal vision or heterozygous (normal vision but carrier for color blindness) for normal vision. In light of this, the couple's daughter will not be color blind.
What is the percent chance that a normal male and a female carrier will have a child who has the disorder?
You might need to indicate what the disorder is.
If a normal woman whose father is color-blind marries a colorblind man what are their chances of having a colorblind son?
50%
How do we calculate probability from bivariate normal distributions?
A calculator for the Bivariate Normal At the bottom of the page at the link, under "A calculator for cumulative probabilities from the bivariate normal distribution" there's a little binary applet, which can be downloaded, and which calculates the percentage chances of being in various parts of the volume of the distribution.
I have an IQ of 136 is that ok for a 12 year old?
Let me guess, from an on line test? Chances are the test was a fake. If however this test was administered and scored by a trained psychologist, than it depends on which test you took. The normal average is 100 for any age.
What would a genetic counselor tell parents who had cystic fibrosis or were carries of the cystic fibrosis about the chances of their children having cystic fibrosis?
If both parents are carriers then the child has a 25% chance of having cystic fibrosis. If one parent has CF and the other the other was just a carrier then the child has a 50% chance of having CF. If one parent has CF and the other has two normal genes then there is no chance of the child having CF. If one parent is a carrier and the other has two normal genes then there is no chance of the child having CF. If both parents have CF then there is a 100% chance that the child will also have CF.
What are the possible phenotypes of the offspring between a parent who is a heterozygous carrier for cystic fibrosis and a homozygous normal parent?
The chances are one half. You will most likley have 2 children without the gene, and 2 with one gene. Since the normal parent has the dominate allele, the Cystic Fiborisis will not be present.
What is the genotype of two normal parents who have a child with cystic fibrosis?
The genotype would have to be homozygous recessive if the child was completely effected by the disease. The "normal" paretns would have to have heterozygous recessive genotypes. This makes sense since the allele that causes sickle cell shows incomplete dominance when present with a normal allele in a pair. The "normal" parents actually would have a mixture of sickle cell shaped red blood cells combined with normal shaped ones. The carrier parents does not display symptoms of the disease since the regular red blood cells alone can fill the body's need for oxygen under normal circumstances. The only time the cArrier would notice would be under times of extreme oxygen demand, such as a sprint.
A couple who are both carriers of the gene for cystic fibrosis have two children who have cystic fibrosis What is the probability that their next child will be phenotypically normal?
If both parents are carriers on cystic fibrosis, just because two children may have the disease it doesn't mean that say,a further 3 children in future will be "normal". Inheriting genes is like a lottery. I can say though that because cystic fibrosis is recessive, every offspring born under carriers will always have a 75% chance of being phenotypically normal.
What does heterozygous have to do with cystic fibrosis?
Individuals with cystic fibrosis have a mutation in the CFTR gene. Being heterozygous for the mutant CFTR gene means having one normal and one mutant copy of the gene, resulting in a carrier state. Carriers are typically unaffected by cystic fibrosis but can pass the mutant gene on to their offspring.
Why can Cystic fibrosis be inherited even if neither parent has the disease?
Cystic Fibrosis is an example of a disease inherited as an autosomal recessive genetic disorder. Both parents of a baby who has Cystic Fibrosis have one abnormal recessive gene and one normal dominant gene and are therefore, Cystic Fibrosis carriers. Carriers are said to be heterozygous because they contain one normal copy of the gene and one abnormal copy. A baby who inherits cystic fibrosis has inherited the abnormal gene from both parents and is therefore said to be homozygous recessive.
What is cystic fibrosis gene disorder?
Cystic fibrosis is a genetic disorder that affects the lungs and digestive system. It is caused by a mutation in the CFTR gene, which leads to the production of thick and sticky mucus that can clog the airways and prevent proper digestion. This can result in respiratory infections and difficulty breathing, as well as problems with nutrient absorption and digestion.
When C equals normal allele and c equals allele for cystic fibrosis Set up and complete a Punnett Square for cystic fibrosis for a couple that both have heterozygous for cystic fibrosis with no sympt?
Sure! When both parents are heterozygous carriers (Cc) for cystic fibrosis, the Punnett Square would result in a 25% chance of having a child with cystic fibrosis (cc), a 50% chance of having a child who is a carrier (Cc), and a 25% chance of having a child who is not a carrier and does not have the disease (CC).
Explain why the parents of someone with cystic fibrosis do not show any symptoms?
In order to have a child with cystic fibrosis, both parents must be carriers (assuming neither of the parents actually have CF; then obviously they will have symptoms). In CF, a carrier has no symptoms, unlike sickle cell anemia, where a carrier will have mild symptoms of the disease. A carrier of CF has only one defected 7th chromosome, and the other unaffected one makes the CFTR gene work correctly. When both are defected, the result is the CF disease, and normal CFTR genes are impossible to make, causing the person to have the disease.
What is the risk in each pregnancy of having a child with cystic fibrosis?
By "another pregnancy", I assume that the parents have had one child with cystic fibrosis. As cystic fibrosis is recessive and neither parent suffers from it, they must both be carriers. That means the chances of the next baby having CF is 25%, or a one in four chance. Assuming both parents have one CF and one non-CF gene, the combinations work out: non-CF x non-CF (normal) non-CF x CF (carrier) CF x non-CF (carrier) CF x CF (cystic fibrosis sufferer) Therefore their chances of having a: normal child = 25% child who is a CF carrier = 50% child who suffers from CF = 25%
What are some facts about cystic fibrosis?
More than 1,000 different mutations in the CFTR gene have been identified in cystic fibrosis patients. The most common mutation (observed in 70% of cystic fibrosis patients) is a three-base deletion in the DNA sequence, causing an absence of a single amino acid in the protein product. About 2,500 babies are born with cystic fibrosis in the U.S. each year. More than 10 million Americans carry the cystic fibrosis gene but don't know it.
What is an example of allele frequency?
An example of allele frequency is when in a population of 100 individuals, 60 individuals have the dominant allele (A) for a specific gene, while 40 individuals have the recessive allele (a). The frequency of the dominant allele (A) would be 0.6, and the frequency of the recessive allele (a) would be 0.4.
