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What are the chances of a normal person and a carrier for cystic fibrosis have a kid with cystic fibrosis?
Zero. Cystic fibrosis is an autosomal recessive disease. This means that both parents must carry a mutated gene and have a 1 in 4 (25%) chance of having a child with CF.
What else can I help you with?
A male who has normal vision marries a female who is a carrier for colorblindness can they have a colorblind daughter?
Assuming that the man who has normal vision is homozygous for normal vision, the couple's daughter will either be homozygous for normal vision or heterozygous (normal vision but carrier for color blindness) for normal vision. In light of this, the couple's daughter will not be color blind.
What is a person who is mucus thicker than normal?
A person with mucus that is thicker than normal may be experiencing a condition known as viscous or hyper-viscous mucus. This can be caused by various factors, including dehydration, certain medical conditions like cystic fibrosis, or respiratory infections. Thick mucus can lead to difficulty breathing or increased risk of infections, as it may obstruct airways or sinuses. Consulting a healthcare professional is advisable for proper diagnosis and management.
What is the percent chance that a normal male and a female carrier will have a child who has the disorder?
You might need to indicate what the disorder is.
If a normal woman whose father is color-blind marries a colorblind man what are their chances of having a colorblind son?
50%
How do we calculate probability from bivariate normal distributions?
A calculator for the Bivariate Normal At the bottom of the page at the link, under "A calculator for cumulative probabilities from the bivariate normal distribution" there's a little binary applet, which can be downloaded, and which calculates the percentage chances of being in various parts of the volume of the distribution.
What would a genetic counselor tell parents who had cystic fibrosis or were carries of the cystic fibrosis about the chances of their children having cystic fibrosis?
If both parents are carriers then the child has a 25% chance of having cystic fibrosis. If one parent has CF and the other the other was just a carrier then the child has a 50% chance of having CF. If one parent has CF and the other has two normal genes then there is no chance of the child having CF. If one parent is a carrier and the other has two normal genes then there is no chance of the child having CF. If both parents have CF then there is a 100% chance that the child will also have CF.
What are the possible phenotypes of the offspring between a parent who is a heterozygous carrier for cystic fibrosis and a homozygous normal parent?
The chances are one half. You will most likley have 2 children without the gene, and 2 with one gene. Since the normal parent has the dominate allele, the Cystic Fiborisis will not be present.
When C equals normal allele and c equals allele for cystic fibrosis Set up and complete a Punnett Square for cystic fibrosis for a couple that both have heterozygous for cystic fibrosis with no sympt?
Sure! When both parents are heterozygous carriers (Cc) for cystic fibrosis, the Punnett Square would result in a 25% chance of having a child with cystic fibrosis (cc), a 50% chance of having a child who is a carrier (Cc), and a 25% chance of having a child who is not a carrier and does not have the disease (CC).
What are is the percentages of a child not having cystic fibrosis with parents who both have the trait?
If both parents are just carriers of the gene that causes CF then there is a 75% chance that the child will not have CF. To break it down farther... 25% chance that they will have CF. 50% that they will be a carrier. 25% that they will have two normal genes.
What is the genotype of two normal parents who have a child with cystic fibrosis?
The genotype would have to be homozygous recessive if the child was completely effected by the disease. The "normal" paretns would have to have heterozygous recessive genotypes. This makes sense since the allele that causes sickle cell shows incomplete dominance when present with a normal allele in a pair. The "normal" parents actually would have a mixture of sickle cell shaped red blood cells combined with normal shaped ones. The carrier parents does not display symptoms of the disease since the regular red blood cells alone can fill the body's need for oxygen under normal circumstances. The only time the cArrier would notice would be under times of extreme oxygen demand, such as a sprint.
A couple who are both carriers of the gene for cystic fibrosis have two children who have cystic fibrosis What is the probability that their next child will be phenotypically normal?
If both parents are carriers on cystic fibrosis, just because two children may have the disease it doesn't mean that say,a further 3 children in future will be "normal". Inheriting genes is like a lottery. I can say though that because cystic fibrosis is recessive, every offspring born under carriers will always have a 75% chance of being phenotypically normal.
What does heterozygous have to do with cystic fibrosis?
people who are heterozygous for cystic fibrosis are not directly affected by the disease (although there is some evidence they have more chance of getting Asama) however they do still carry the gene for CF (they are carriers) this means if they have kids with another carrier they have a 25% chance of having a CF positive child (out of four one non effected, two carriers, and one diseased)
Why can Cystic fibrosis be inherited even if neither parent has the disease?
Cystic Fibrosis is an example of a disease inherited as an autosomal recessive genetic disorder. Both parents of a baby who has Cystic Fibrosis have one abnormal recessive gene and one normal dominant gene and are therefore, Cystic Fibrosis carriers. Carriers are said to be heterozygous because they contain one normal copy of the gene and one abnormal copy. A baby who inherits cystic fibrosis has inherited the abnormal gene from both parents and is therefore said to be homozygous recessive.
Which is a genetic disorder that gene therapy may correct?
Cystic fibrosis is a genetic disorder that gene therapy may correct by introducing a healthy copy of the CFTR gene into cells to restore normal function in affected individuals.
Explain why the parents of someone with cystic fibrosis do not show any symptoms?
In order to have a child with cystic fibrosis, both parents must be carriers (assuming neither of the parents actually have CF; then obviously they will have symptoms). In CF, a carrier has no symptoms, unlike sickle cell anemia, where a carrier will have mild symptoms of the disease. A carrier of CF has only one defected 7th chromosome, and the other unaffected one makes the CFTR gene work correctly. When both are defected, the result is the CF disease, and normal CFTR genes are impossible to make, causing the person to have the disease.
What is cystic fibrosis gene disorder?
The genes on each chromosome control specific functions of the human body. The gene on chromosome 7 produces a protein called cystic fibrosis transmembrane regulator. Mutation in the DNA level of chromosome 7 leads to the absence of this protein which leads to cystic fibrosis. Cystic fibrosis is a recessive disease. It means that both copies of the gene must be defective. An affected person will have abnormal cystic fibrosis transmembrane regulator gene on each chromosome 7. Therefore both biological parents must have an abnormal gene. One abnormal copy is inherited from each parent. A person with one normal gene and one abnormal gene is called a cystic fibrosis carrier. Cystic fibrosis carriers do not show any symptoms but they may pass the abnormal gene to their children. Therefore the parents can be either cystic fibrosis carriers or affected themselves.
What is the risk in each pregnancy of having a child with cystic fibrosis?
By "another pregnancy", I assume that the parents have had one child with cystic fibrosis. As cystic fibrosis is recessive and neither parent suffers from it, they must both be carriers. That means the chances of the next baby having CF is 25%, or a one in four chance. Assuming both parents have one CF and one non-CF gene, the combinations work out: non-CF x non-CF (normal) non-CF x CF (carrier) CF x non-CF (carrier) CF x CF (cystic fibrosis sufferer) Therefore their chances of having a: normal child = 25% child who is a CF carrier = 50% child who suffers from CF = 25%
