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Q: What would be the best way to predict the probability of a baby having Christic fibrosis?
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What is the probability of a child having cystic fibrosis if one of her parents was homozygous dominant and the other was a carrier for cystic fibrosis?

The probability of a child having cystic fibrosis in this scenario is 50%. If one parent is homozygous dominant (no cystic fibrosis allele) and the other is a carrier (heterozygous), there is a 50% chance of passing on the cystic fibrosis allele to their child, resulting in the child having cystic fibrosis.


Which of the following calculations require that you utilize the addition rule?

The addition rule is used when calculating the probability of two mutually exclusive events occurring together. For example, when calculating the probability of rolling a 2 or a 6 on a six-sided die, you would use the addition rule.


What does a punnet square mean?

A Punnett square is a diagram used to predict the probability of offspring having specific genotypes based on the genotypes of the parents. It helps visualize the potential genetic outcomes of a mating.


What is the probability of two healthy people where one is a carrier being parents to a child born with cystic fibrosis?

If only one person is a carrier of cystic fibrosis than there is no chance of having a child with it. Both parents have to be carriers and even then there is only a 25% chance. If only one carries than there is a 50% chance that their children will carry but will not have cystic fibrosis.


What is a punnett square for cystic fibrosis?

A Punnett square for cystic fibrosis would involve crossing two parents who are carriers of the recessive allele for the disease (denoted as "cf"). The square would show the probability of having a child with cystic fibrosis (25%), a carrier (50%), or unaffected by the disease (25%). Each parent would have a genotype of "Cf" (carrier) for the Punnett square.


A man and a woman who do not have cystic fibrosis get married have two children who have the disease they want to try and have a third childwhat is the probability of the third having the disease?

same probable as the first child having it. By doing the punnet square, they are both recessive for the disease. There is a 25% chance that the child will get the disease.


Why do males with Cystic Fibrosis have a very small chance of having kids?

because 95% of men with cystic fibrosis are sterile


How do you deterime phenotypes?

phenotypes are decided by the alleles for that particular characteristic, by a dominant or two recessive alleles. For example, cystic fibrosis has a recessive allele so the phenotype of cystic fibrosis would only appear if there were two of the recessive allele, one from each parent, were present. A heterozygous carrier of the cystic fibrosis allele would show the phenotype of not having cystic fibrosis. So to determine the phenotype simply find out which allele is dominant and find what alleles each parent has the the probability of each phenotype can be calculated


If the probability of a defect is 0.015 what is the probability of not having a defect?

1-.015 = .985


What is the probability of having a son?

50%


What mathematical term is used in having the same probability?

Equiprobable, but I would stick with simplicity of communication and go with "having the same probability".


What would a genetic counselor tell parents who had cystic fibrosis or were carries of the cystic fibrosis about the chances of their children having cystic fibrosis?

If both parents are carriers then the child has a 25% chance of having cystic fibrosis. If one parent has CF and the other the other was just a carrier then the child has a 50% chance of having CF. If one parent has CF and the other has two normal genes then there is no chance of the child having CF. If one parent is a carrier and the other has two normal genes then there is no chance of the child having CF. If both parents have CF then there is a 100% chance that the child will also have CF.