0
...from what? Is is essential to know the properties of the items you are drawing from.
If the question applies to a deck of cards (which the wording alludes to), then the probability is 1/13.
There are 4 9's in a deck of cards, and there are 52 total cards. 4/52=1/13
Add your answer:
Earn +20 pts
What is probability of drawing 10 of 52 cards?
If you draw 9 or fewer cards, the probability is 0. If you draw 10 or more card, the probability is 1.
What is the probability of both marbles being red if there are 6 red and 4 blue and 2 were drawn without replacing them?
First draw probability of red is 6/10. If first draw is red, then second draw probability of red is 5/9. Multiply the two probabilities to get the overall probability. 6/10 X 5/9 = 30/90 = 1/3
What is the probability of drawing a diamond from a normal deck of cards?
If you draw 40 cards without replacement the probability is 1! If you draw just one, the probability is 1/4.
What is the probability of drawing a heart in a deck of cards?
The probability, if you draw 40 cards, without replacement, is 1. That is, it is a certainty. The probability on a single random draw is 1/4.
What is the probability of get ace of spades on first draw and get queen of hearts on second draw?
The probability of drawing the Ace of Spades on the first draw is 1 in 52. The probability of drawing the Queen of Hearts on the second draw is 1 in 51. The probability of both of those event occurring is 1 in 2652. (1 in 52) times (1 in 51)
What is probability of drawing 10 of 52 cards?
If you draw 9 or fewer cards, the probability is 0. If you draw 10 or more card, the probability is 1.
What is probability of drawing a seven or a nine out of cards?
Probability of drawing a 7 or 9 is the probability of draw a 7 plus the probability of draw a 9 which is 4/52 + 4/52 = 8/52 = 2/13 = 0.1538.
What is the probability of both marbles being red if there are 6 red and 4 blue and 2 were drawn without replacing them?
First draw probability of red is 6/10. If first draw is red, then second draw probability of red is 5/9. Multiply the two probabilities to get the overall probability. 6/10 X 5/9 = 30/90 = 1/3
What is the probability of drawing of exactly one 9 if you draw two cards without replacement from a deck of cards?
Let's call the chance of drawing a 9 on the first draw P(A). Since there are four 9s, P(A) is 4/52. Probability of not drawing a 9 is 1-(4/52). Each draw is independent so we multiply the probabilities. The probability of EXACTLY one 9 in two draws if P(A)P(1-A)=12/169 which is a about .071
What is the probability of drawing a seven of hearts?
The probability on a single random draw, from a normal deck of cards, is 1/52.The probability on a single random draw, from a normal deck of cards, is 1/52.The probability on a single random draw, from a normal deck of cards, is 1/52.The probability on a single random draw, from a normal deck of cards, is 1/52.
What is the probability you will draw a U not replace it then draw an M from the word summer?
In the first two draws, the probability is 1/15.
What is the probability of drawing a diamond from a normal deck of cards?
If you draw 40 cards without replacement the probability is 1! If you draw just one, the probability is 1/4.
What is the probability of drawing a heart in a deck of cards?
The probability, if you draw 40 cards, without replacement, is 1. That is, it is a certainty. The probability on a single random draw is 1/4.
What is the probability of get ace of spades on first draw and get queen of hearts on second draw?
The probability of drawing the Ace of Spades on the first draw is 1 in 52. The probability of drawing the Queen of Hearts on the second draw is 1 in 51. The probability of both of those event occurring is 1 in 2652. (1 in 52) times (1 in 51)
You have a 3-card deck containing a king a queen and a jack you draw a random card then put it back and draw a second random card calculate the probability that you draw exactly 1 jack?
1 - the chance to draw 2 jacks - the chance to draw no jacks leaves you with the chance to draw just one by elimination. 1 - (1/3)*(1/3) - (2/3)*(2/3) 1 - 1/9 - 4/9 1 - 5/9 4/9
Are these events dependent or independent You draw a card replace it then draw another card?
They are independent, because the probability of the first event does not affect the probability of the second event.
What is the probability of drawing an 8 followed by a 2 from 11 numbers?
If the number 8 is PUT BACK INTO the group after the first draw, the probability of drawing an 8 then a 2 from 11 numbers is: 0.8% or eight-tenths of a percent [reason #1]If the number 8 is REMOVED from the group after the first draw, the probability of drawing an 8 then a 2 from 11 numbers is: 0.9% or nine-tenths of a percent [reason #2]Reason # 1 :On the first draw, you have a 1 in 11 chance of drawing the 8 (9%) then on the second draw there is again a 1 in 11 chance of drawing the 2 (9%). So 9% x 9% = 0.8% or 8/10 % (or 0.008)Reason # 2 :On the first draw, you have a 1 in 11 chance of drawing the 8 (9%) then on the second draw you only have a 1 in 10 chance of drawing the 2 (10%). So 9% x 10% = 0.9% or 9/10 % (or 0.009) OR If the first ball is removed, the odds are 55 to 1.
