As an algebraic term: 16n
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Let the consecutive integers be 'n' & 'n+1'. Their product is n(n+1) Their sum is n + n+ 1 = 2n + 1 Eight timres the sum is 8(2n+1) Their product being 8 less that their sum is n(n+1) = 8(2n+1) - 8 Hence n^(2) + n = 16n + 8 - 8 n^(2) + n = 16n n^(2) = 15n ( Cancel down by 'n'). n = 15 n+1 = 16 Hence '15' & '16' are the two numbers.
The product of 416 and 16 is 6656.
Product of 320 and 16 is 5120.
let n = {...-2,-1,0,1,2,3,4,...} then n+1 is the consecutive number. Their product is n(n+1) = n2 + n
It is n! or n factorial.