10 : 13
3
10.'384615' (recurring decimals) feet
6 feet
25 feet tall
The ratio of the shadow cast to the height of an object will be the same at the same time of day. For the fence post, the height of the post is 2.5 times the length of the shadow ( 5 ft / 2 ft = 2.5 ) The tree has a 10 foot shadow, so using the same ratio for the fence post: 10 ft * 2.5 = 25 feet. The tree is 25 feet tall
3
We can solve this problem using a ratio. Since a 6 foot man casts a 4 foot shadow we can write this ratio as 6:4. If we reduce this ratio we get 3:2. Now we're stating that for every 3 feet of height, the shadow cast will be 2 feet.Now we can work our problem out using a small table:3 feet of flag pole = 2 feet of shadow6 feet of flag pole = 4 feet of shadow9 feet of flag pole = 6 feet of shadow12 feet of flag pole = 8 feet of shadow15 feet of flag pole = 10 feet of shadow18 feet of flag pole = 12 feet of shadowTherefore an 18 foot flag pole will cast a 12 foot shadow at the same time that a 6 foot man casts a 4 foot shadow.
The tree is 25 feet tall. A 5 foot pole cast a 2 foot shadow. This means that the sun angle causes the shadow to be 2/5 the length of the object casting it. The tree's shadow is 10 feet tall. Multiply 10 feet by 5/2 (inverting the fraction because we're going the other way) and we get 25 feet.
A 10-foot pole is equivalent to 304.8 centimeters.
63 feet
10.'384615' (recurring decimals) feet
140*10/6 = 233.33... ft or 233 ft 4 inches. Except at that distance, the end of the shadow would be too diffuse to measure accurately.
It depends what time of day it is.
The flag pole would be 20 feet. (You can see that the shadows are twice as long.) At a given time of the day, the length of a shadow cast by any object will have the same relationship to its actual height as all other objects. Here the ratio is 5/10 = x/40 and multiplying both sides by 40, 20 = x.
6 feet
In therory, infinitely long. In practice, the shadow will fade into dispersed light.
Yes I would, if their regular handler was in the pen with me.