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In the absence of a proper statement of the equation I can only guess at answers. How about (2x + 3)(3x - 5) which is the factorisation of 6x2 - x - 15 = 0? In which case x = -2/3 or 5/3.
First step should be to take everything to the left side:6x2 - 18x - 12 = 0Next you might divide by the common factor, 6:x2 - 3x - 2 = 0It seems you have to use the quadratic formula for this one. Use a = 1, b = -3, c = -2.First step should be to take everything to the left side:6x2 - 18x - 12 = 0Next you might divide by the common factor, 6:x2 - 3x - 2 = 0It seems you have to use the quadratic formula for this one. Use a = 1, b = -3, c = -2.First step should be to take everything to the left side:6x2 - 18x - 12 = 0Next you might divide by the common factor, 6:x2 - 3x - 2 = 0It seems you have to use the quadratic formula for this one. Use a = 1, b = -3, c = -2.First step should be to take everything to the left side:6x2 - 18x - 12 = 0Next you might divide by the common factor, 6:x2 - 3x - 2 = 0It seems you have to use the quadratic formula for this one. Use a = 1, b = -3, c = -2.
6x2
Taking the equation to be y=ax2 + bx +c , and using the formula x = -b plus/minus sqrt (b2-4ac), all over 2a: x = (-3+21)/12 or (-3-21)/12 so x = 1.5 or -2
the equation 6x^2 - 4x + 25 is a quadratic equation due to the 6x^2 term. Whatever number on the x squared term changes it to a quadratic equation if you were to get rid of the 6x^2 then the equation would simply be -4x+25 making it simply a linear equation. when ever you have an x raised to 2 that term is the quadratic term in the equation.