This is an expression, not an equation. Expressions cannot be solved.
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9y2+66y+121 = (3y+11)(3y+11) when factored
x3+27y3 = (x+3y) · (x2-3xy+9y2)
It depends on where there are parentheses, if there are any. y + 33 + 2/4 = y + 27.5 (y+3)3 + 2/4 = y3 + 9y2 + 27y + 27.5
If Y = y, then it is 9y4 or 9Y4. If Y is not the same as y, then you can't simplify it any.
-4x2 + 9y2 + 16x - 18y +29 = 0 (I hope this is what you meant) 9y2 - 18y - (4x2 -16x) +29 = 0 (group together the x's and y's, and make the x2 term positive. 9(y2 - 2y) - 4(x2 - 4x) +29 = 0 (remove common factors) 9(y - 1)2 - 1 - 4(x - 2)2 - 4 + 29 = 0 (complete the squares) 9(y - 1)2 - 4(x - 2)2 = -25 (move constants to right-hand side) [(y - 1)2] - 4[(x - 2)2]/9 = -25/9 (divide by coefficient in front of x or y bracket, in this case 9) [(y - 1)2]/4 - [(x - 2)2]/9 = -25/36 (divide by coefficient in front of other bracket, in this case 4) As you can see, we now have our equation in standard form. Our center points satisfy [(x - 2 = 0) , (y - 1 = 0)], thus our center is (2,1).