No. Y=3X2+1 is a Binomial Equation.
x = +/- sqrt(y/3)
The value of x is 2
The answer depends on the domain for x. For example, if the domain is x = 7, then the range is 55. If the domain is all Real numbers, then the range is y >= 6.
The question contains an expression, not an equation and so there is no solution.
3x2-y=6 3x2-y=6
No. Y=3X2+1 is a Binomial Equation.
x = +/- sqrt(y/3)
The domain and range are both [-6, +6].
The value of x is 2
The answer depends on the domain for x. For example, if the domain is x = 7, then the range is 55. If the domain is all Real numbers, then the range is y >= 6.
The question contains an expression, not an equation and so there is no solution.
A quadratic equation is an equation where the highest exponent on the variable is 2. For example, the equation, y=2x2+3x-2 is a quadratic equation. The equation y=2x is not quadratic because the highest exponent on x is 1. (If there is no exponent on an x, then the exponent is 1.) The equation, y=x3+3x2-2 is not quadratic because the highest exponent is three. On a graph, a quadratic equation looks like a U or and upside down U. Here are some more example of quadratic equations: y=x2 y=3x2+2x-3 y=x2+5
(a) y = -3x + 1
Without an equality sign it can not be considered to be an equation and the - or + value of 9x has not been given
y > -8
The tangent to 2x3 - 3x2 - 8x + 9 at x = 2 is y = 4x - 11 The tangent to y = 2x3 - 3x2 - 8x + 9 at x = 2 has the same gradient as the curve at that point; to find the gradient, differentiate: dy/dx = 6x2 - 6x - 8 which at x = 2 is: gradient = 6 x 22 - 6 x 2 - 8 = 4 At x = 2, y = 2 x 23 - 3 x 22 - 8 x 2 + 9 = -3 The equation of a line through point (xo, yo) with gradient m is: y - yo = m(x - xo) Thus the equation of the tangent to the line at x = 2 is: y - -3 = 4(x - 2) ⇒ y = 4x - 11