y = -4x2 + 1 Range = {y:y=<1, y is an element of the reals}
Which equation can have the following domain and range? {x | 8 ≤ x ≤ 14} {y | 29 ≤ y ≤ 53}Answer this question…
The domain and range of the equation y = 2x+8 are both [-infinity,+infinity].
-8
"y 2x 8" makes not too much sense.. if you meant y = 2x + 8(which you probably did), the range (or how far y can possibly go) is pretty much infinite. The range can go from negative infinity to positive infinity. To infinity, and beyond!
y = -4x2 + 1 Range = {y:y=<1, y is an element of the reals}
No. [ y = 4x2 ] is a quadratic equation.
y=4x2+3x+8
yes
Which equation can have the following domain and range? {x | 8 ≤ x ≤ 14} {y | 29 ≤ y ≤ 53}Answer this question…
The domain and range of the equation y = 2x+8 are both [-infinity,+infinity].
-8
"y 2x 8" makes not too much sense.. if you meant y = 2x + 8(which you probably did), the range (or how far y can possibly go) is pretty much infinite. The range can go from negative infinity to positive infinity. To infinity, and beyond!
Without an equality sign the given terms can't be considered to be a quadratic equation.
The equation y = 4x^2 + 5 is a parabola
4x2-y2 = (2x-y)(2x+y)
Interpreting this equation as y=4x3+4x2 This is not a quadratic equation. By definition, a quadratic equation is a polynomial equation of order two, meaning it is composed only of coefficients multiplied by x's raised to any exponential power of maximum 2. The most that any of the exponents in the equation can be is 2. Since this equation has a term of 4x3, it is not quadratic since this term has an exponent of 3. This means that the equation is of degree three. This equation is a cubic equation.