A function is an equation that gives a unique answer. A relation does not. Example: y = 3x + 1 is a function. If I give you x, you can determine y. And that y is unique to that x. So if x = 1, you know y = 4. No other of x gives y = 4 as an answer. So y = 3x + 1 is a function. Example: y = 4x2. So if I give you x = 1, y = 4. But y = 4 if I also give you x = -1. So y = 4x2 is not a function, it is a relation.
y > -8
y < 1
The domain is from negative infinity to positive infinity. The range is from positive 2 to positive infinity.
absolute value of y> 1
A function is an equation that gives a unique answer. A relation does not. Example: y = 3x + 1 is a function. If I give you x, you can determine y. And that y is unique to that x. So if x = 1, you know y = 4. No other of x gives y = 4 as an answer. So y = 3x + 1 is a function. Example: y = 4x2. So if I give you x = 1, y = 4. But y = 4 if I also give you x = -1. So y = 4x2 is not a function, it is a relation.
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Assuming the first function is y = 4x2 + 1, and the second y = 4x2 then the first graph is 1 unit higher than the second.
y > -8
First you need to solve for y. So write 4x2+y=16 so y=16-4x2 Now write f(x)=16-4x2
y < 1
The domain is from negative infinity to positive infinity. The range is from positive 2 to positive infinity.
absolute value of y> 1
The answer will range between '2' & '-2' Reason; The Sine function ranges between '1' & '-1' , so if it has a coefficient of '2', this will increase the range to '2' & '-2'.
yes
We have f(x) = y = 4x2 When x = 1, f(1) = 4(1)2 = 4 and when x = -1, f(-1) = 4(-1)2 = 4 So for negative and positive values of x, y is always positive. So y = 4x2 opens upward. Visit the link mentioned below to know more about the given function.
Maybe; the range of the original function is given, correct? If so, then calculate the range of the inverse function by using the original functions range in the original function. Those calculated extreme values are the range of the inverse function. Suppose: f(x) = x^3, with range of -3 to +3. f(-3) = -27 f(3) = 27. Let the inverse function of f(x) = g(y); therefore g(y) = y^(1/3). The range of f(y) is -27 to 27. If true, then f(x) = f(g(y)) = f(y^(1/3)) = (y^(1/3))^3 = y g(y) = g(f(x)) = g(x^3) = (x^3)^3 = x Try by substituting the ranges into the equations, if the proofs hold, then the answer is true for the function and the range that you are testing. Sometimes, however, it can be false. Look at a transcendental function.
4x2-y2 = (2x-y)(2x+y)